Answer:
<u>B. 1/2 and 1.</u>
Step-by-step explanation:
The coefficient of a variable is the number that the variable is being multiplied for. In this example. We can see that x² is being multiplied by 1/2, therefore <u>1/2 is one of the coefficients</u>.
In the case of x, it doesn't have a number before it, it means that it's being multiplied by 1. Hence, our <u>second coefficient is 1</u>.
Race track principle says that if two functions are equal at <span>t=0</span>, then the one which has a greater derivative will be greater.
In this case we're comparing <span><span>f′</span>(t)</span> and <span><span>g′</span>(t)</span>. So we make sure that <span>g(0)=<span>f′</span>(0)</span> and that <span><span>f′′</span>(t)≥<span>g′</span>(t)
</span>
<span>g(t)=at+b</span>
Since it is a line.
<span><span>g′</span>(t)=a</span>
<span><span>f′′</span>(t)≥3≥<span>g′</span>(t)⟹3≥a</span>
So let <span>a=3</span>.
<span><span>f′</span>(0)=0=g(0)=3(0)+b⟹b=0
</span>So that means
<span>g(t)=3t
</span>Do something similar for <span>h(t)</span><span> starting with
</span><span>h(t)=a<span>t2</span>+bt+c
</span><span>h(0)=f(0)⟹c=0
</span>
So
<span>h</span><span>(</span><span>t</span><span>)</span><span>=</span><span>a</span><span>t2</span><span>+</span><span>b</span><span>t</span>
9514 1404 393
Answer:
Step-by-step explanation:
The form of the equation you are given is called "point-slope" form. The "slope" in this case is the per-hour fee. The point is (9 h, $195). Point-slope form generally looks like this:
y -k = m(x -h) . . . . . line with slope m through point (h, k)
Here, you have m=15, (h, k) = (9, 195), so the equation looks like ...
y -195 = 15(x -9)
__
The "one-time fee" is the cost when hours are zero.
y -195 = 15(0 -9)
y = 195 -9(15) = 60 . . . . add 195 to both sides, and evaluate
The one-time fee is $60.
I hope this helps you
132-x+6x-12=180
5x=60
x=12
6y+18+132-x=180
6y+150-12=180
6y=42
y=7
Area = 80 sq yards
height = 10 yards
80 = .5* 10 * base
base = 16
