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GrogVix [38]
3 years ago
7

B

Mathematics
1 answer:
morpeh [17]3 years ago
6 0

Answer:

first option

Step-by-step explanation:

I'm not really sure myself but I think the first option is the best option to choose because the others aren't really that true and if you look the angle c is much bigger than the other angles so I think the first option is more likely

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What is the product in simplest form −6/11⋅3/4
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What is the expression in radical form?<br><br> (4x3y2)310
sertanlavr [38]

Given:

Consider the given expression is

(4x^3y^2)^{\frac{3}{10}}

To find:

The radical form of given expression.

Solution:

We have,

(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

Therefore, the required radical form is \sqrt[5]{8y^3}\sqrt[10]{x^9}.

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3 years ago
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2 years ago
Anyone know the answer to this
Vesna [10]

Answer:

Part A:

- angle ACB= 60° (ABC equilateral triangle.)

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   = 180°-134°

   = 46°

x= 46°

Part B:

120°

3 0
2 years ago
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