2 years ago

Find the zeros of y=x^2-8x-3

1 answer:

4 0

This is gonna be the answer. It’s 4+sqrt(19) and 4-sqrt(19). Which is approximately 8.36 and -0.36. In x intercept form, it’s (8.36,0) and (-0.36,0) also I solved this by completing the square. I hope this helps!!! Mark as brainliest!!!

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Find the zeros of y=x^2-8x-3​

Find the zeros of y=x^2-8x-3