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yan [13]
3 years ago
7

Find the zeros of y=x^2-8x-3​

Mathematics
1 answer:
Anton [14]3 years ago
4 0
This is gonna be the answer. It’s 4+sqrt(19) and 4-sqrt(19). Which is approximately 8.36 and -0.36. In x intercept form, it’s (8.36,0) and (-0.36,0) also I solved this by completing the square. I hope this helps!!! Mark as brainliest!!!

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Step-by-step explanation:

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Step-by-step explanation:

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Find the lengths of the missing side . Simplify all radicals !!!<br> help mee!!!!!!
larisa86 [58]

Answer:

e = 13\sqrt{2}

f = 13\sqrt{2}

Step-by-step explanation:

The ∆ given is an isosceles ∆ with a right angle measuring 90°, and two congruent angles measuring 45° each.

Using trigonometric ratio formula, we can find the lengths of the missing side as shown below:

Finding e:

sin(\theta) = \frac{opp}{hyp}

sin(\theta) = sin(45) = \frac{\sqrt{2}}{2}

hyp = 26

opp = e = ?

Plug in the values into the formula

\frac{\sqrt{2}}{2} = \frac{e}{26}

Multiply both sides by 26

\frac{\sqrt{2}}{2}*26 = \frac{e}{26}*26

\frac{\sqrt{2}}{2}*26 = e

\frac{\sqrt{2}}{1}*13 = e

13\sqrt{2} = e

e = 13\sqrt{2}

Since side e is of the same length with side f, therefore, the length of side f = 13\sqrt{2}

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Step-by-step explanation:

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