Find the zeros of y=x^2-8x-3

Mathematics

1 answer:

Anton [14]2 years ago

4 0

This is gonna be the answer. It’s 4+sqrt(19) and 4-sqrt(19). Which is approximately 8.36 and -0.36. In x intercept form, it’s (8.36,0) and (-0.36,0) also I solved this by completing the square. I hope this helps!!! Mark as brainliest!!!

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2•log(x – 3) = log 25

AfilCa [17]

Answer:

Step-by-step explanation:

2log(x-3)=log25

log(x-3)²=log25 cancel out log on both sides

(x-3)²=25

x²-6x+9=25

x²-6x+9-25=0

x²-6x-16=0 factorize

x²+2x-8x-16=0

x(x+2)-8(x+2)

(x-8)(x+2)=0

x-8=0 or x+2=0

x=8 or x=-2

x=-2 cannot be considered because of the -ve sign.

x=8.

check

2log(x-3)

2log(8-3)

2log5

log5²=25

therefore LHS=RHS

8 0

2 years ago

a cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. the material for the sides of the can costs

fredd [130]

The dimensions of the can are radius of can = 4cm and

height of can = 78.6cm

What is the volume of cylinder?

A cylinder can be seen as a collection of multiple congruent disks, stacked one above the other. In order to calculate the space occupied by a cylinder, we calculate the space occupied by each disk and then add them up.

Thus, the volume of the cylinder can be given by the product of the area of base and height.

Volume of cylinder = πr²h

According to the given question:

We have V cylinder = V = 400cc

We will first find the areas involved

Let x = radius of base then area of the base = π*x² and this is the area of the top too

For lateral area we need to get h the height of the cylinder as function of x

V = πx²h ⇒ h= v/πx² ⇒ h = 400/πx²

Now the total area of the cylinder is:

A(x) = Area of the base + area of the top + lateral area

A(x) = 2*π*x² + 2πx h ⇒ A(x) = 2*π*x² + 2πx (V/πx² )

A(x) = 2*π*x² + 800/x