1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

(

)
Answer:
y = 2
Step-by-step explanation:
6y - 2(y + 1) = 3(y - 2) + 6
6y - 2y - 2 = 3y - 6 + 6
6y - 2y - 2 = 3y
4y - 2 = 3y
4y - 2 + 2 = 3y + 2
4y = 3y + 2
4y - 3y = 3y - 3y + 2
y = 2
Answer:
so the vertex is (-4, 0) and the axis of symmetry is x=-4
Step-by-step explanation:
f(x) ≥ -(x+4)^2
f(x) ≥ -(x- -4)^2
this is in the form
f(x)> a(x-h)^2 +k
where (h,k) is the vertex and h is the axis of symmetry
so the vertex is (-4, 0) and the axis of symmetry is x=-4
Answer:
You add all of the sides... or you can multiply one side with 4.
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The answer is 1/10 x (9a-23b)