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larisa86 [58]
2 years ago
10

Hey guys! I am going to be posting multiple questions, but one by one... so be prepared!

Mathematics
1 answer:
Mashcka [7]2 years ago
8 0

Answer:

\frac{110}{3}    or     36\frac{2}{3}

Step-by-step explanation:

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Dmitry [639]
So base on the question that describe the Amanda's jewelry box that is in shape of a cube and has a measurement of 6 inch on on its edge, to calculate the volume of the said cube, you must multiply the said number to the power of 3 and with that, the volume would be 216 cubic inches
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Which situation shows a constant rate of change?
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2 years ago
Write an equation in slope intercept form for the line that passes through (-1, -2) and (3, 4)
LenaWriter [7]

Answer:

The slope-intercept form of the line equation  is:

  • y=\:\frac{3}{2}x\:-\frac{1}{2}

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the points

  • (-1, -2)
  • (3, 4)

Determining the slope between (-1, -2) and (3, 4)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-1,\:-2\right),\:\left(x_2,\:y_2\right)=\left(3,\:4\right)

m=\frac{4-\left(-2\right)}{3-\left(-1\right)}

m=\frac{3}{2}

Thus, the slope of the line is:

m = 3/2

substituting m = 3/2 and the point (3, 4) in the slope-intercept form of the line equation

y = mx+b

4=\frac{3}{2}\left(3\right)+b

switch sides

\frac{3}{2}\left(3\right)+b=4

\frac{9}{2}+b=4

subtract 9/2 from both sides

\frac{9}{2}+b-\frac{9}{2}=4-\frac{9}{2}

b=-\frac{1}{2}

now substituting m = 3/2 and b = -1/2 in the slope-intercept form of the line equation

y = mx+b

y=\:\frac{3}{2}x\:+\:\left(-\frac{1}{2}\right)

y=\:\frac{3}{2}x\:-\frac{1}{2}

Therefore, the slope-intercept form of the line equation  is:

  • y=\:\frac{3}{2}x\:-\frac{1}{2}
8 0
2 years ago
Why is 6√3 irrational or rational?
Oduvanchick [21]

Answer:

irrational.

Step-by-step explanation:

√3 is irrational.

product of rational and irrational number is always irrational.

6×√3=6√3

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mars1129 [50]
  • 3x+y=8--(1)

2x+4y=12

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  • (1)×1 and (2)×3

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\\ \rm\Rrightarrow 3x+6y=18

Subtract both

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\\ \rm\Rrightarrow y=\dfrac{-10}{-5}

\\ \rm\Rrightarrow y=2

Put the value in eq(2)

\\ \rm\Rrightarrow x+2(2)=6

\\ \rm\Rrightarrow x+4=6

\\ \rm\Rrightarrow x=6-4=2

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2 years ago
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