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3 years ago

Graph the image of this figure after a dilation with a scale factor of 2 centered at (2, 2).

Mathematics

1 answer:

Maru [420]3 years ago

6 0

Answer:

(-6,6), (0,12), (4,8)

Step-by-step explanation:

To dilate an object, we need to multiply the x and y values by the given scale factor.

In this case the scale factor is 2 --> 2(x, y)

Before-> After dilation

2(-3,3) = (-6,6)

2(0,6) = (0,12)

2(2,4) = (4,8)

Please leave a 'thanks' if this helps!

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Last year, the total revenue for Home Style, a national restaurant chain, increased 5.25% over the previous year. If this trend

Setler [38]

Answer:

Monthly percent increase in revenue = 0.4273%.

Step-by-step explanation:

Let m = number of months in time period.

We have that: Annual increase based on annual rate = Annual increase based on monthly rate * 12.

To find the increase in the original amount, we use the formula:

$A_{0}(1 + i)^{n}$ , where n = number of time periods and i = interest rate.

Therefore,

Ao(1 + ia) = Ao(1 + im)m,

$A_{0}(1 + i_{a} )^{n_{a} } = A_{0}(1 + i_{m} )^{n_{m} }$

where Ao= original amount, ia = annual interest rate, im = monthly interest rate, na = number of annual time periods, nm = number of monthly time periods.

$n_{a}=1; n_{m}=m$

$A_{0}(1 + i_{a} ) = A_{0}(1 + i_{m} )^{m}$

Divide both sides by Ao

$(1 + i_{a}) = (1 + i_{m} )^{m}$

Taking the mth root of both sides

$(1 + i_{a})^{\frac{1}{m}}= 1 + i_{m}$

$i_{m} = (1 + i_{a})^{\frac{1}{m}}-1$

$i_{a}= 5.25*1/100 = 0.0525\\m = 12$

$i_{m} = (1 + 0.0525)^{\frac{1}{12}}-1\\i_{m} = (1.0525)^{\frac{1}{12}}-1 = 1.004273 - 1\\i_{m} = 0.004273 * 100\\i_{m} = 0.4273$

$i_{m}=$ 0.4273%

Thus, the monthly revenue increase of Home Style is 0.4273%.

3 0

3 years ago

Coach Dom took the football team out for pizza. He bought 6 pies at $6.35 each. He left a 18 % tip. How much did Coach Dom spend

Travka [436]

Answer: $44.96

Step-by-step explanation:

6 × 6.35 = 38.1

38.1 × .18 = 6.86

38.1 + 6.86 = 44.96

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3 years ago

A statistician selected a sample of 16 accounts receivable and determined the mean of the sample to be $5,000 with a standard de

Anon25 [30]

Answer:

The confidence level that was used is 0.25% .

Step-by-step explanation:

We are given that mean of the selected sample of 16 accounts is $5,000 and a standard deviation of $400.

It has also been reported that the sample information indicated the mean of the population ranges from $4,739.80 to $5,260.20. This represents the Confidence Interval for population mean.

But we have to find that at what confidence level this information about range of population men has been stated.

Since we know that Confidence Interval for population mean is given by :

C.I. for population mean = Sample mean(xbar)  $\pm$  z value *  $\frac{Standard deviation}{\sqrt{n} }$ 

i.e.,if we have 95% C.I. = xbar $\pm$ 1.96 * $\frac{\sigma}{\sqrt{n} }$ .

So, our Confidence Interval for population is written as :

[$4,739.80 , $5,260.20] = $5000 $\pm$ z value * $\frac{400}{\sqrt{16} }$

$5000 - z value * 100 = $4739.80 { Solving these we get Z value = 2.602}

$5000 + z value * 100 = $5260.20

In z table we find that at value of 2.60 the probability is 0.99534 so subtracting this from 1 we get confidence level for one tail i.e.0.5%(approx).

Therefore, for two tail Confidence level will be 0.5%/2 = 0.25% .

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3 years ago

Raeana is twice as old as Madeline, and Laura is 10 years older than Raena. If Laura is 50 years old, how old is Madeline? Defin

laiz [17]

Answer: Madeline is 20 yrs old

Step-by-step explanation:

If Laura is 50 and she is 10 years older than Raena then Raena is 40 that would then make Madeline 20 years old.

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4 years ago

A display of seed packets contains 24 zucchini seed packets and 28 other seed packets. What is the probability that a randomly s

Nonamiya [84]

Answer:

The probability is 6/13

Step-by-step explanation:

Number of zucchini seed packets = 24

Number of other seed packets = 28

Total number of packets = 24 + 28 = 52

Probability is given by

$P(E)=\frac{n(E)}{n(s)}\\\\n(E)=24,n(s)=52\\P(E)=\frac{24}{52}\\\\P(E)=\frac{6}{13}$

Hence, the required probability is 6/13

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3 years ago