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Tamiku [17]
3 years ago
10

Randal builds and sells cabinets. When deciding what price to charge for a project, he considers the cost of materials and the t

ime he will spend on the project. (He charges $18 per hour of labor.) Then he adds 15 percent for operational costs. Andrea’s cabinets will require $2,125 of materials and 80 hours of labor. How much will Randal charge for Andrea’s cabinets?
Mathematics
2 answers:
LenaWriter [7]3 years ago
7 0

Answer:

Randal will charge $4099.75.

Step-by-step explanation:

Randal builds and sells cabinets.

He charges $18 per hour of labor. While pricing, he considers the cost of materials and the time he will spend on the project. Then he adds 15% for operational costs.

Andrea’s cabinets will require $2,125 of materials and 80 hours of labor.

So, total charges will be : 2125+80(18)=3565 dollars

Now 15% operational costs on $3565 is :

0.15\times3565=534.75 dollars

So, the total cost Randal will charge =3565+534.75=4099.75 dollars.

Therefore, Randal will charge $4099.75.

marta [7]3 years ago
6 0

Answer:

3781

Step-by-step explanation:

80 hours × $18=$1440 for labor. 1440+15%(1440×.15)=$216.00 + material cost=$2125

(2125.00+1440.00+216=3781)

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3 years ago
3<br> 4<br> 5<br> 5<br> (1,-1)?<br> -17<br> 2t<br> -37<br> -44<br> (x + 4.7 - 5<br> -5<br> What does y-5 represent
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3 years ago
The endpoints of one diagonal of a rhombus are (-7, -2) and (-1, -4). If the coordinates of the 3rd vertex are (-6, -9), what ar
podryga [215]

The coordinates of the 4th vertex of the rhombus are (-2,3)

<h3>How to determine the coordinates of the 4th vertex?</h3>

The diagonals are given as:

(-7, -2) and (-1, -4)

The 3rd vertex is given as: (-6,-9)

Calculate the distance between the vertices of the diagonals and the 3rd vertex using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}

So, we have:

d_1 = \sqrt{(-7 + 6)^2 + (-2 + 9)^2} =\sqrt{50

d_2 = \sqrt{(-1 + 6)^2 + (-4 + 9)^2} =\sqrt{50

Let the 4th vertex be (x,y)

So, we have:

d_3 = \sqrt{(-7 - x)^2 + (-2 - y)^2} =\sqrt{50

d_4 = \sqrt{(-1 - x)^2 + (-4 - y)^2} =\sqrt{50

Equate d3 and d4

\sqrt{(-1 - x)^2 + (-4 - y)^2} = \sqrt{(-7 - x)^2 + (-2 - y)^2}

Take the square of both sides

(-1 - x)^2 + (-4 - y)^2 = (-7 - x)^2 + (-2 - y)^2

Expand

1 + 2x + x^2 + 16 + 8y + y^2 = 49 + 14x + x^2 + 4 + 4y + y^2

Evaluate the like terms

1 + 2x  + 16 + 8y  = 49 + 14x + 4 + 4y

Collect like terms

14x - 2x + 4y - 8y = 1 + 16 - 49 - 4

12x - 4y = -36

Divide through by 4

3x - y = -9

Next, we test the options in the above equation

Point (-8,13) means x = -8 and y = 13

So, we have:

3x - y = -9

3(-8) - 13 = -9

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Point (-2, 3) means x = -2 and y = 3

So, we have:

3x - y = -9

3(-2) - 3 = -9

-9 = -9 --- this is true.

Hence, the coordinates of the 4th vertex are (-2,3)

Read more about rhombus at:

brainly.com/question/20627264

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sergejj [24]
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Identify the slope, y-intercept, write the equation and zero of the line on the graph.
Oxana [17]

Answer:

0,-4 is the y-intercept and y2+x is the equation I think

Step-by-step explanation:

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