Answer:
The large sample n = 190.44≅190
The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44
<u>Step-by-step explanation</u>:
Given population proportion was estimated to be 0.3
p = 0.3
Given maximum of error E = 0.04
we know that maximum error
The 85% confidence level 
now calculation , we get
√n=13.80
now squaring on both sides n = 190.44
large sample n = 190.44≅190
<u>Conclusion</u>:-
Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44
You just add the values for volunteers that worked 16-20 hours and 21-25 hours which would be 50 + 10 = 60. So the total number of volunteers that workers more than 15 hours is 60.
We need to find the number of pies baked in years 1 and 2.
There were 148 pies baked in year 1. 
There were 
pies baked in year 2. 
Rearrange the terms so the variable is first. 
No Alan did not break even
Alan incured a loss of 6.25 %
<em><u>Solution:</u></em>
Given that,
Alan bought two bikes
He sold one to Beth for $300 taking a 25% loss
He also sold one to Greta for $300 making a 25% profit
When a person sells two similar items, one at a gain of say x%, and the other at a loss of x%, then the seller always incurs a loss
Which is given as:
Here, x = 25
Thus the loss percentage is 6.25 %
![\bf \textit{parabola vertex form}\\\\ \boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\ x=a(y-{{ k}})^2+{{ h}}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -----------------------------\\\\ y=a(x-h)^2+k\qquad \begin{cases} h=-2\\ k=-3 \end{cases}\implies y=a[x-(-2)]^2-3 \\\\\\ y=(x+2)^2-3](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bparabola%20vertex%20form%7D%5C%5C%5C%5C%0A%5Cboxed%7By%3Da%28x-%7B%7B%20h%7D%7D%29%5E2%2B%7B%7B%20k%7D%7D%7D%5C%5C%5C%5C%0Ax%3Da%28y-%7B%7B%20k%7D%7D%29%5E2%2B%7B%7B%20h%7D%7D%5Cqquad%5Cqquad%20%20vertex%5C%20%28%7B%7B%20h%7D%7D%2C%7B%7B%20k%7D%7D%29%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Ay%3Da%28x-h%29%5E2%2Bk%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ah%3D-2%5C%5C%0Ak%3D-3%0A%5Cend%7Bcases%7D%5Cimplies%20y%3Da%5Bx-%28-2%29%5D%5E2-3%0A%5C%5C%5C%5C%5C%5C%0Ay%3D%28x%2B2%29%5E2-3)
expand the binomial, either binomial theorem, or just FOIL
bear in mind, we're assuming the coefficient "a" is 1
and we're also assuming is the first form, it could be the second, but we're assuming is a vertical parabola
