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galben [10]
2 years ago
6

One building is 3ft by 20ft if the other building is 21ft by ——— what is the height

Mathematics
1 answer:
cestrela7 [59]2 years ago
3 0
The other building is 21ft by 140ft.
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The area of the triangle is 5.88 square centimeters.what is the length of the base.the heights is 2.1
Bas_tet [7]

Answer:

base = 5.6 cm

Step-by-step explanation:

area of a triangle = 1/2 * base * height

area = 5.88 cm²

height = 2.1 cm

5.88 = 1/2 * base * 2.1

5.88 = 1.05 base

5.88 / 1.05 = base

base = 5.6 cm

4 0
3 years ago
At Candyland Daycare there are 7 children to every 2 caretakers. If there are 35 children at the daycare, then how many caretake
OLga [1]
10
because you would do 35 divided by 7 which is 5.
5 x 2 is 10
8 0
3 years ago
Read 2 more answers
7(2x+5) = 11x-9-x <br><br> Please HELP
mr_godi [17]

Step-by-step explanation:

7(2x+5)=11x-9-x

14x+35=10x-9

4x+35=-9

4x=-44

x=-11

3 0
3 years ago
One kind of bacteria in a laboratory culture triples every 30 minutes. Suppose the culture is started with 20 bacteria cells. Ho
IgorC [24]

Answer:

2 hours = 4 * 30 minutes

30 * 3 = 90

90 * 3 = 270

270 * 3 = 810

810 * 3 = 2430

So after 2 hours you will have 2430 bacteria cells.

Step-by-step explanation:

3 0
3 years ago
Can u help me please better picture
gladu [14]

Hi, there.

For this question, we can apply the Pythagorean theorem a^2 + b^2 = c^2.

I'm sure you've seen this equation before, and they kind of tried to trip you up with this problem. Trust me, it's easier than it looks. Let's break it down.

Lengths a and b both have the value of 48, which means that the value s in \sqrt{2s^2} is 48, because the length of the hypotenuse is the same as the length and height squared multiplied by 2.

Plug in the value for c: a^2 + b^2 = (\sqrt{2s^2})^2

Plug in the value for s:

(\sqrt{2(48^2)})^2

Do the innermost exponents first:

(\sqrt{2(2304)})^2

The square root symbol and the power of 2 cancel each other out, so we are left with:

s = 2(2304), so the hypotenuse is 4608 inches.

4 0
3 years ago
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