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Cerrena [4.2K]
3 years ago
12

How is the heat energy of water related to the temperature of water?

Biology
1 answer:
guajiro [1.7K]3 years ago
4 0

Answer:

Explanation:

One of water's most significant properties is that it takes a lot of heat to it to make it get hot. Precisely, water has to absorb 4,184 Joules of heat (1 calorie) for the temperature of one kilogram of water to increase 1°C. For comparison sake, it only takes 385 Joules of heat to raise 1 kilogram of copper 1°C.

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Why does the bread easily get molds than the rice​
Marina CMI [18]

Answer:

The sugar content

Explanation:

Bacteria are attracted to sugar, so maybe, they try to get the sugars and mold the bread.

3 0
3 years ago
Why are there so few aquatic plants and phytoplankton that live at the bottom zones in the ocean?
noname [10]

Answer:

ocean is good

Explanation:

7 0
3 years ago
Read 2 more answers
8. Two rabbits are bred together. One is heterozygous for agouti coat
dusya [7]

Answer:

- Parental cross = Cch  x chch  

- F1 = 1/2 Cch (agouti coat); 1/2 chch (albino coat) >> 1:1 phenotypic ratio

Punnett  square:  

          ch         ch

C       Cch       Cch

ch    chch      chch

 

Explanation:

A heterozygous individual is an individual who has two different gene variants (i.e., alleles) at a particular <em>locus</em>. In this case, individuals having the "agouti coat" trait are heterozygous carrying both 'C' and 'ch' alleles. On the other hand, a homo-zygous individual has the same allele at a given <em>locus</em> (here, the 'chch' genotype associated with the albino phenotype). Therefore, as observed in the Punnett Square above, when a heterozygous parent is crossed with a homo-zygous recessive parent for a single gene, alleles segregate in the gametes of both parents so an expected 1:1 phenotypic ratio will be observed.

4 0
3 years ago
In watermelons, bitter fruit (B) is dominant to sweet fruit (b), and yellow spots (S) are dominant to no spots (s). The genes fo
lubasha [3.4K]

If an F1 plant is backcrossed with the sweet, unspotted parent, the phenotypic proportion that is expected in the offspring will be in the ratio of 1:1:1:1.

<h3>What is Backcross?</h3>

Backcross may be defined as a type of cross where the F1 hybrid is crossed with either the recessive or dominant traits.

This question typically represents a dihybrid cross implicating two genes, one coding for fruit taste and the other for spot color. The allele for bitter taste (B) and yellow spot (S) is dominant over the allele for sweet taste (b) and no spot (s) respectively.

So, a heterozygous F1 resulting from a cross between a purebred dominant (bitter fruit, yellow spot) and purebred recessive (sweet fruit, no spot) will have a BbSs genotype.

When the F1 hybrid BbSs is backcrossed with the sweet, unspotted parent (bbss), the phenotypes with their proportions are given below:

  • Bitter fruit, yellow spot (BbSs, 1)
  • Bitter fruit, no spot (Bbss, 1)
  • Sweet fruit, yellow spot (bbSs, 1)
  • Sweet fruit, no spot (bbss, 1).

The Punnett square of this cross is described below:

Therefore, if an F1 plant is backcrossed with the sweet, unspotted parent, the phenotypic proportion that is expected in the offspring will be in the ratio of 1:1:1:1.

To learn more about Dihybrid cross, refer to the link:

brainly.com/question/8083392

#SPJ1

7 0
2 years ago
Which direction does heat flow from?
Sedaia [141]
B) cold to hot hope this helps
6 0
3 years ago
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