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Neporo4naja [7]
3 years ago
6

The sum of the numbers j,k, and m is 115. The ratio of j to k is 2:7 and the ratio of k to m is 14:5. What is the value of k?

Mathematics
2 answers:
I am Lyosha [343]3 years ago
8 0

Answer:

I know how to help you.

Step-by-step explanation:

There is a web site called Khan Academy and it can help you understand how to solve it and it is completely free and you can use it as much as you want. There are videos that explain it to you and problems like help with practice I 100% reccomend it!

JulijaS [17]3 years ago
7 0

Answer:

f. 70

Step-by-step explanation:

I did this question in another brainly problem, but ok. So first k has to be able to divide by 14 and 7. Divided all the answers by 7 first. Then 14. Only 70 is able to divide by 7 and 14. Lastly check to see if it works. 2:7 = 20=70. 14:5 = 70:25. 20+70+25=115.

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lyudmila [28]

Answer:

In the explanation :)

Step-by-step explanation:

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I believe this is right but I'm not sure anymore with today's math

5 0
3 years ago
{ PLEASE ANSWER QUICKLY, PROBLEM DUE ASAP } The functions f(x) and g(x) are defined below. Which expression is equal to f(x) + g
8090 [49]

Answer:

Option C. 2x + 20 / x² + 6x – 40

Step-by-step explanation:

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7 0
3 years ago
Rewrite each item as an equivalent expression in exponential notation. <br> 5^6x5^9
TiliK225 [7]
5^6 * 5^9

= 5^(6 + 9)

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I hope this helps. =)
5 0
3 years ago
More math and its my last question
vaieri [72.5K]

We know that ∠1 equals ∠3, from that we can find x:

10x = 100 \\ x = 10

The sum of ∠1 and ∠2 must equal 180°:

10x + 10y + 20 = 180

Since we already know x, we can solve for y:

10 \times 10 + 10y + 20 = 180 \\ 10y + 120 = 180 \\ 10y = 60 \\ y = 6

Result: x=10, y=6

4 0
3 years ago
5/x^2-5x - x/5x-25 simplify
Debora [2.8K]
\bf \cfrac{5}{x^2-5x}-\cfrac{x}{5x-25}\implies \cfrac{5}{x(x-5)}-\cfrac{x}{5(x-5)}\impliedby \stackrel{LCD}{5x(x-5)}&#10;\\\\\\&#10;\cfrac{25-x^2}{5x(x-5)}\implies \cfrac{5^2-x^2}{5x(x-5)}\implies \cfrac{\stackrel{\textit{difference of squares}}{(5-x)(5+x)}}{5x(x-5)}&#10;\\\\\\&#10;\cfrac{\boxed{-\underline{(x-5)}}(5+x)}{5x\underline{(x-5)}}\implies \cfrac{-(5+x)}{5x}\implies \cfrac{-5-x}{5x}
7 0
3 years ago
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