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saveliy_v [14]
3 years ago
12

4x^-2*y/x*y^-2 step by step

Mathematics
1 answer:
ehidna [41]3 years ago
8 0

Answer: 4 x square 3 y

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Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m
marshall27 [118]

Answer:

1. 0.0000454

2. 0.01034

3. 0.0821

4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,  

X \sim Poi(\lambda = 10)

1. Requires us to compute

P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454

2.  We need to compute P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)

P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454

P(X =2) = e^{-10} \frac{10^2}{2!} = 0.00227

P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757

P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034

3. The expected no. of arrivals in a 15 second period is = 10 \times \frac{1}{4} = 2.5. So if Y be the random variable denoting number of passengers arriving in 15 seconds,

Y \sim Poi(2.5)

P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821

4. Here we use the fact that Y can take values 0,1, \dotsc. So, the event that "Y is either 0 or \geq 1" is a sure event ( i.e it has probability 1 ).

P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918

3 0
3 years ago
M is the centroid of the triangle.<br> CM=7, PM=10, &amp; BQ=18<br> M<br> AM=[?]<br> Is it 6?
Snowcat [4.5K]

Answer:

5

Step-by-step explanation:

6 0
3 years ago
Mass of a Robin was 72.89 grams the mass of a blue Jay was 84.28 grams what is the estimate difference in the mass of the birds
pentagon [3]

Answer:

Step-by-step explanation:

estimation: 84-73

11

5 0
3 years ago
The sum of 5 consecutive odd numbers is 505
pentagon [3]

Answer:

In a sequence of 5 numbers, the 3rd number is the middle number. So in your problem the third number is the average of the 5 numbers -- which is the sum of the numbers, divided by how many there are: 505/5 = 101.

Explanation:

8 0
3 years ago
In △ABC , line AB is extended up to point E and line BC is extended up to D . The measure of some of the angles is given as; ∠BA
Over [174]

Answer:

\angle ACD = 130 ^\circ.

Step-by-step explanation:

\angle ABC and \angle EBC are supplementary angles. Their sum should be 180^\circ.  \angle EBC = 120^\circ \implies \angle ABC = 180^\circ - \angle EBC = 180^\circ - 120^\circ = 60^\circ.

The sum of the three angles in triangle \triangle ABC: (\angle ABC + \angle BAC + \angle ACB) should be equal to 180^\circ.

\angle ABC = 60^\circ and \angle BAC = 70^\circ \implies \angle ACB = 180^\circ - \angle ABC - \angle ACB = 180^\circ - 70^\circ - 60^\circ = 50^\circ.

\angle ACB and \angle ACD form another pair of supplementary angles. Their sum should also be 180^\circ. \angle ACB = 50^\circ \implies \angle ACD = 180^\circ - \angle ACB = 180^\circ - 50^\circ = 130^\circ.

8 0
4 years ago
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