M is the centroid of the triangle. CM=7, PM=10, & BQ=18 M AM=[?] Is it 6?

A lake has a large population of fish. On average, there are 2,400 fish in the lake, but this number can vary by as much as 155.

AleksAgata [21]

Answer:

Minimum population of fish in lake = 2400 - 155 = 2245

Maximum population of fish in lake = 2400 + 155 = 2555

Step-by-step explanation:

population of fish in lake = 2400

Variation of fish = 155

it means that while current population of fish is 2400, the number can increase or decrease by maximum upto 155.

For example

for increase

population of fish can 2400 + 2, 2400 + 70, 2400 + 130 etc

but it cannot be beyond 2400 + 155.

It cannot be 2400 + 156

similarly for decrease

population of fish can 2400 - 3, 2400 - 95, 2400 - 144 etc

but it cannot be less that 2400 - 155.

It cannot be 2400 - 156

Hence population can fish in lake can be between 2400 - 155 and 2400 + 155

minimum population of fish in lake = 2400 - 155 = 2245

maximum population of fish in lake = 2400 + 155 = 2555

4 0

3 years ago

Do the data in the table represent a direct variation or an inverse variation write an equation to model the data in the table.

astraxan [27]

The answer is C. xy=40

6 0

4 years ago

Read 2 more answers

Y=−2x+1 x−3y=11 find the solution using elimination.

yawa3891 [41]

Answer:

Step-by-step explanation:

Using first equation in the second gives you

x-3(-2x+1)=11

x+6x-3=11

7x-3=11

7x=14

x=2, making y=-2x+1 become

y=-2(2)+1

y=-4+1

y=-3 so the solution is the point

(2,-3)

3 0

3 years ago

Will mark brainliest

AlekseyPX

E and C. 2:5 and salt:pepper

8 0

3 years ago

At a certain time of the day, a tree that is x meters tall casts a shadow that is x-49 meters long. If the distance from the top

nikklg [1K]

The height of the tree is 60 meters.

Explanation:

Let the height of the tree be x. The tree casts a shadow of $x-49$ meters and the distance from the top of the tree to the end of the shadow is $x+1$ meters.

The sides of the triangle are attached in the image below:

Using pythagoras theorem,

$x^{2}+(x-49)^{2}=(x+1)^{2}$

Expanding, we get,

$2 x^{2}-98 x+2401=x^{2}+2 x+1$

$2 x^{2}-98 x+2400=x^{2}+2 x$

$2 x^{2}-100 x+2400=x^{2}$

$x^{2}-100 x+2400=0$

Solving the equation using the quadratic formula $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , we get,

$x=\frac{-(-100)\pm\sqrt{(-100)^{2}-4 \cdot 1 \cdot 2400}}{2 \cdot 1}$

Simplifying, we have,

$x=\frac{100\pm\sqrt{10000-9600}}{2}$

$x=\frac{100\pm\sqrt{400}}{2}$

$x=\frac{100\pm{20}}{2}$

Thus,

$x=\frac{100+20}{2} \\x=\frac{120}{2} \\x=60$ and $x=\frac{100-20}{2} \\x=\frac{80}{2} \\x=40$

where the value $x=40$ is not possible because substituting the value $x=40$ in $x-49$ results in negative solution. Which is not possible.

Hence, the value of x is 60.

Thus, The height of the tree is 60 meters.

7 0

3 years ago