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kkurt [141]
3 years ago
15

What is x + 2y = 10 in slope form

Mathematics
2 answers:
Alenkasestr [34]3 years ago
6 0

Answer:

x+2y-10=0

x=10-2y

x=10

Step-by-step explanation:

what is slope form?

Oksanka [162]3 years ago
3 0
The answer is Y= -1/2x +5
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What is the value of x + 3y + z if x = 4, y = 5, and z=2?​
Alexus [3.1K]

Answer:

x+3y+z=21

Step-by-step explanation:

x+3y+z

4+3(5)+2

4+15+2

21

8 0
3 years ago
Read 2 more answers
The time required to finish a test in normally distributed with a mean of 70 minutes and a standard deviation of 10 minutes. Wha
zalisa [80]
Note that 60 minutes is 1 standard deviation away from the mean and from recalling the 68-95-99.7 rule, the area that will remain is (100 - 68) = 32%. However, we only want the leftmost portion of this area, so the answer is 32%/2 = 16%. 

<span>Choose D.</span>
3 0
3 years ago
Find the equation of the line with a slope of -3, passing through the point (2,5).
Alexxx [7]
Y = -3(2) + 11
y = -6 + 11
y = 5

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8 0
3 years ago
Simplify the difference. (–7x – 5x^4 + 5) – (–7x^4 – 5 – 9x)
sineoko [7]

Answer: 2x^4+2x+10

Step-by-step explanation:

You need to remember the mulplication of signs:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-

Knowing this, you can distributive the negative sign. Then you get:

(-7x- 5x^4 + 5) - (-7x^4 - 5 - 9x)=-7x- 5x^4 + 5 +7x^4 + 5 + 9x

Now you need to add the like terms. Then:

=2x+2x^4+10

Finally, you can order the polynomial obtained in descending order. Therefore, the answer is:

=2x^4+2x+10

4 0
3 years ago
The "mammals" data set in the "MASS" library contains the result of a study of sleep in mammal species. 1 2 Load the "mammals" d
dusya [7]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

The probability that the random you randomly select species that are greater than 200 kg is  = 7/62

Step-by-step explanation:

Step One: Load the data set in to the R work space

data(mammals,package="MASS")

attach(mammals)

Step 2 : Obtain the list of the species that are greater than 200  and store it on y variable.

y <- subset(mammals,body>200)

Step Three : Obtain the total size

nrow(mammals)

Step Four : Obtain the  sum of species greater than 200

sum(body > 200)

total size = 62

size with body > 200 = 7

hence

required probability = 7/62

7 0
3 years ago
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