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Klio2033 [76]
3 years ago
9

Emma pays $108 every six weeks for tennis lessons. What is the price per year for tennis lessons?

Mathematics
2 answers:
koban [17]3 years ago
7 0
Okay so divide 52 weeks by 6 weeks  and multiply that quotient by 108$
ss7ja [257]3 years ago
3 0

Answer:

$936

Step-by-step explanation:

Number of weeks in 1 year= 52 weeks

Cost of every six week for tennis lesson= $108

We have to find the price per year for tennis lessons

Number of times he will pay for the tennis lessons= \frac{52}{6}

Total price per year for Tennis lessons= \frac{52}{6} × 108

Total price per year for Tennis lessons= 52 × 6

Total price per year for Tennis lessons= $ 936

Hence, the correct answer is $ 936

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Convert 60/36 to a mixed number
Alekssandra [29.7K]
1\frac{24}{36} because 36 goes into 60 1 time with 24 left over
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3 years ago
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A piece of property lies between two parallel streets as shown. m<1=(2x+6)°,and m<2=(3x+9)°. What is the relationship betw
kolezko [41]
  • The angles are supplementary angles
  • The measure of angle m<1 and m<2 are 72 and 108 degrees respectively

Find the diagram attached. From the figure, the sum of the angles m<1 and m<2 are supplementary

Given the following angles

m<1 = 2x + 6

m<2 = 3x + 9

Since both angles are supplementary, hence;

2x + 6 + 3x + 9 = 180

5x + 15 = 180

5x = 180 - 15

5x = 165

x = 165/5

x = 33

Get the measure of m<1;

m<1 = 2x + 6

m<1 = 2(33) + 6

m<1 = 66 + 6

m<1 = 72degrees

Get the measure of m<2:

m<2 = 180 - m<1

m<2 = 180 - 72

m<2 = 108degrees

Hence the measure of angle m<1 and m<2 are 72 and 108 degrees respectively

Learn more here: brainly.com/question/22309882

5 0
2 years ago
If the common difference in an article is -3 and the first term is 7 what is the 14th term?
Wittaler [7]
I got A, -32, but it has been awhile since I have learned this in my math class. You might want to wait for someone else to verify this answer. 
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3 years ago
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A local grocery story has strawberries on sale for $1.45 per pound. How much would it cost to buy 5.5 pounds of strawberries? Ro
myrzilka [38]

Answer: The cost of 5.5 pounds strawberries =$ 7.98

Step-by-step explanation:

Given: A local grocery story has strawberries on sale for $1.45 per pound.

i.e. Cost for 1 pound strawberries = $1.45

Now, Cost of 5.5 pounds strawberries =  5.5 x (Cost for 1 pound strawberries)

= $ (5.5 x  1.45)

= $ 7.975 ≈ $ 7.98   [ Round to the nearest penny]

Hence, the cost of 5.5 pounds strawberries =$ 7.98

5 0
3 years ago
34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
2 years ago
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