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1 answer:
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Answer:
option D
Step-by-step explanation:
x=-1 and x=-3 are the real zeros
We plug in the x values in each equation and check which equation makes y=0
A) y=x^4-4x^3-4x^2-4x-3
x=-1 ,
x=-3 ,
y is not equal to 0 so option A is not correct
B.y=-x^4-4x^3+4x^2+4x+3
x=-1 ,
x=-3 ,
y is not equal to 0 so option B is not correct
C.y=x^4+4x^3+3x^2+4x-4
x=-1 ,
x=-3 ,
y is not equal to 0 so option C is not correct
D) y=x^4+4x^3+4x^2+4x+3
x=-1 ,
x=-3 ,
y=0 so option D has two real zeros x=-1 and x=-3