Question

Shortly after a vinyl record (radius 0.152 m) starts rotating on a turntable, its angular velocity is 1.60 rad/s and increasing at a rate of 8.00 rad/s2. At this instant, for a point at the rim of the record, what is the tangential component of acceleration

Answer 1

Answer:

$a_{t} = 1.216\,\frac{m}{s^{2}}$

Explanation:

The tangential component of acceleration is equal to the product of radius and angular acceleration:

$a_{t} = (0.152\,m)\cdot (8\,\frac{rad}{s^{2}} )$

$a_{t} = 1.216\,\frac{m}{s^{2}}$