Answer:
(a) -16.7 N s; (b) -167 N
Explanation:
Given: m = 0.530 kg; vi = 18.0 m/s; vf = 13.5 m/s; t = 0.100 s
Find: (a) Impulse, (b) Force
(a) Impulse = Momentum Change = m•Delta v = m•(vf - vi)= (0.530 kg)•( -13.5 m/s - 18.0 m/s)
Impulse = -16.7 kg•m/s = -16.7 N•s
where the "-" indicates that the impulse was opposite the original direction of motion.
(Note that a kg•m/s is equivalent to a N•s)
(b) The impulse is the product of force and time. So if impulse is known and time is known, force can be easily determined.
Impulse = F•t
F = Impulse/t = (-16.7 N s) / (0.100 s) = -167 N
where the "-" indicates that the impulse was opposite the original direction of motion.
Answer:C
Explanation:
Given
Overload mass =90 Pounds
and 1 Pound=0.453 kg
90 Pounds=40.823 kg
Density of Gasoline 
Volume of Gasoline for this mass 
and 
is equal to 264.172 Gallon
therefore 0.05451 m^3 is equal to 14.40 Gallons which is approximately equals to 15 Gallon
Answer:
a) For the passenger the ball is seen to go up in a straight line path, and fall back to the hands of the passenger in a straight line path.
b) For a stationary observer on the ground, the ball is seen to take a parabolic path from when it is thrown up to when it fall down back on the palms of the passenger.
Explanation:
If a ball is thrown up in a vehicle moving with a constant velocity, the ball will be seen as the passenger, who is on the same frame of reference as the ball, to go up and down in a vertical straight line path. For an observer on the ground, this is different, as the ball is seen to to have both a relative vertical and horizontal component of motion, making the ball take a parabolic path from the time it was thrown, to when it falls back to the hands of the passenger.
