Do (7x3)=21x7=147 so that’s how you do it hope it helps
Answer:
- x = 30°
- DB = 26
- AD = BC = AB = DC = 7
Step-by-step explanation:
- <em>Diagonals of a square are congruent and perpendicular and bisect each other</em>
<h3>Q4</h3>
m∠AEB = 3x
m∠AEB = 90°
<h3>Q5</h3>
AE = 3x - 2
EC = 2x + 3
- AE = EC
- 3x - 2 = 2x + 3
- 3x - 2x = 3 + 2
- x = 5
DB = EC = 2(AE) = 2(3*5 - 2) = 2(13) = 26
<h3>Q6</h3>
<u>AD and BC are the sides, which are equal</u>
- 2x - 1 = 5x - 13
- 5x - 2x = 13 - 1
- 3x = 12
- x = 4
AD = BC = AB = DC = 2*4 - 1 = 7
I am putting this into rows. Ex: row one has 0. row two has blank and seven.
1: 0
2: 9 7
3: - 9 6
4: 1 3
5: - 1 2
6: 1
So the answer on top would be 8 1 r 1.
23^(a+b). 23 raised to the power of a+b
The answer is 4.8
(4 tenths and 4 tenths = 8 tenths )