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Elena L [17]
3 years ago
12

Which function matches g? Two hook shaped graphs, f and g, on a coordinate plane. The graph of f has three line segments: negati

ve 2 comma 2 decreases to negative 1 comma negative 1 then horizontal to 1 comma 1, then increases to 2 comma zero. The graph of g has three longer line segments: negative 1 comma 4 decreases to zero comma negative 2, then horizontal to 2 comma negative 2, then increases to 3 comma zero. Group of answer choices g(x) = f(x – 2) g(x) = 2f(x – 1) g(x) = f(x – 1) g(x) = 2f(x – 2)

Mathematics
1 answer:
avanturin [10]3 years ago
8 0

Answer:

Option (2).

Step-by-step explanation:

Coordinates of points A(-2, 2), B(-1, -1), C(-1, 4) and (0, -2)

By using formula to get the length of any segment having extreme ends at (x_1,y_1) and (x_2,y_2),

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Length of segment AB = \sqrt{(-2+1)^2+(2+1)^2}

                                      = \sqrt{10} ≈ 3.16

Length of segment CD = \sqrt{(0+1)^2+(-2-4)^2}

                                      = \sqrt{37} ≈ 6.08

Length of CD ≈ 2(length of AB)

But length of horizontal segments are equal.

Therefore, function 'f' is vertically stretched to form 'g'.

g(x) = 2f(x)

Now 'f' is translated by 1 unit right,

g(x) = 2f(x - 1)  

Option (2) will be the answer.

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Answer:

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Step-by-step explanation:

I'm never sure how far to go on these questions but I think what I'e done looks pretty nice. Essentially I simplified each radical, factored out each variable, combined the radicals after more simplification, and then picked the answer you were most likely looking for. I gave some alternatives in my work that are "simple" too, but the answer above is most likely I'd say.

Work is in the attachment, comment with any questions.

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The length of time for one individual to be served at a cafeteria is a random variable having an exponential distribution with a
irga5000 [103]

Answer:

P(Y \geq 5)= 0.0729+0.0158+0.00146=0.0902

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n, p)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Solution to the problem

Let Y the random variable that represent the lenght of time for one individual to be served at the cafeteria. We know from the probalem that Y\sim exp(\mu=4)

On this case the probability density function would be given by:

f(y) =\frac{1}{4} e^{-\frac{y}{4}}, y\geq 0

And 0 for other case. In order to solve this problem we need to fidn first the probability that a person would be served in less than 2 minutes. And in order to find it we need to find the cumulative distribution function integrating the density function like this:

P(Y \leq 2) = \int_{0}^3 f(y) dy

=\int_{0}^3 \frac{1}{4}e^{-\frac{y}{4}} dy

=-e^{-\frac{y}{4}} \Big|_0^2 \ =1-e^{-\frac{2}{4}}=1-e^{-\frac{1}{2}}=0.3935

And with this probability we can find the probability that a person would be served in less than 2 minutes on at least 5 of the next 7 days.

And on this case we can use the binomial distribution, and we want this probability:

P(Y \geq 5)= P(Y=5) +P(Y=6) +P(Y=7)

We can find the individual probabilities like this:

P(Y=5)=(7C5)(0.3935)^5 (1-0.3935)^{7-5}=0.0729

P(Y=6)=(7C6)(0.3935)^6 (1-0.3935)^{7-6}=0.0158

P(Y=7)=(7C7)(0.3935)^7 (1-0.3935)^{7-7}=0.00146

P(Y \geq 5)= 0.0729+0.0158+0.00146=0.0902

7 0
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iVinArrow [24]

Answer:

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Step-by-step explanation:

plug them in

-4=3(-2)+2 find if its true

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do the next one

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-4=6-4

-4≠2

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