3 years ago

Please help I will give you a thanks I really need help

Mathematics

1 answer:

jeka943 years ago

4 0

For #13 it is -1. Sorry I couldn't do the other ones...

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HELP ME PLZ ASAPPPPPP

boyakko [2]

Answer:

$(x,y) =(-4,-3)$ --- Vertex

$x = -4$ --- Axis of symmetry

Step-by-step explanation:

Given

$y = -6(x + 4)^2 - 3$

Solving (a): The vertex

For an equation written in

$y = a(x - h)^2 + k$

The vertex is:

$(x,y) = (h,k)$

By comparison:

$y = a(x - h)^2 + k$ and $y = -6(x + 4)^2 - 3$

$-h =4$ $k = -3$

$h =-4$ $k = -3$

So, the vertex is:

$(x,y) =(-4,-3)$

Solving (b): The axis of symmetry

For an equation written in

$y = a(x - h)^2 + k$

The axis of symmetry is:

x = h

In (a):

$h =-4$

So:

$x = -4$

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