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nikitadnepr [17]
3 years ago
5

In acid solution, water can add to the double bond of 2-butenedioic acid to form 2-hydroxysuccinic acid.

Chemistry
1 answer:
satela [25.4K]3 years ago
6 0
So, what is the question?
You might be interested in
[20pts] I want to start counterfeiting American pennies. Each penny weighs 2.56g and I want $200.00 of pennies for my scheme. Se
Lera25 [3.4K]

Answer:

    \$200.00\times 100\dfrac{penny}{\$}\times \dfrac{2.56g}{penny}\times \dfrac{1molCu}{63.5gCu}\times \dfrac{2molAl}{3molCu}\times \dfrac{27gAl}{1molAl}

Explanation:

The <em>dimensional analysis</em> helps you by focusing your attention into the units: you must set up the equation starting with the available units and add the factors with the units such that the cancelation of numerators and denominators ends up with the desired units: grams of aluminium in this case.

In this case, you start with a mass of 2.56 grams per penny, which is 2.56g/penny, whose value is $200.00 and want to end with the grams of

Aluminium needed.

Then, you must use the mole ratios derived from the chemical equation in a way that the units lead from grams of copper to grams of aluminium.

The equation is:

           2Al(s)+3CuCl_2(aq)\rightarrow 2AlCl_3(aq)+3Cu(s)

From which, the mole ratio between copper and aluminium is:

           2molAl(s):3molCu(s)\\\\\dfrac{2molAl}{3molCu},or\\\\\\\dfrac{3molCu}{2molAl}

You must also use the atomic masses of Cu and Al which are 63.5g/mol and 27g/mol respectively.

The equation is:

     

          \$200.00\times 100\dfrac{penny}{\$}\times \dfrac{2.56g}{penny}\times \dfrac{1molCu}{63.5gCu}\times \dfrac{2molAl}{3molCu}\times \dfrac{27gAl}{1molAl}

You can check that afeter multiplying all the factors, the most units will cancel and the final units will be grams of Al.

8 0
3 years ago
Carbohydrate metabolic enzymes bind D-glucose specifically. D-glucose has an estimated caloric value of 1 k.cal per 4 grams of c
Aleksandr [31]

Answer:

D) 0 k.cal per 4 grams

Explanation:

Genarally, glucose can be classified into two enantiomers such as d-glucose and l-glucose. The d-glucose is the most common sugar that bodies of living organisms use as source of energy. However, l-glucose is an organic compound and it is one of the aldohexose monosaccharides. It is the l-isomer of glucose and commonly refer to as a low-calorie sweetener. The l-glucose is  relatively indistinguishable in taste from d-glucose but cannot be used as a source of energy. Therefore, in the given problem:

if d-glucose has an estimated caloric value of 1 k.cal per 4 grams of carbohydrate, then the caloric value of l-glucose will be 0 k.cal per 4 grams.

3 0
3 years ago
Is a radioactive gas that forms in rocks<br> underground.
Amiraneli [1.4K]

Answer:

Radon gas.

Explanation:

It forms naturally from the decay (breaking down) of radioactive elements, such as uranium, which are found in different amounts in soil and rock throughout the world. Radon gas in the soil and rock can move into the air and into underground water and surface water.

6 0
3 years ago
Why is neon in the same group as helium on the periodic table
belka [17]
<span>The noble gases are the six elements that make up Group 18 of theperiodic table: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). At one time, this family of elements was also known as the rare gases.</span>
8 0
3 years ago
Jay and Jeff were responsible for recording the class weather data each day in march. What weather instrument, seen here, should
snow_tiger [21]
What are the instruments
5 0
3 years ago
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