Answer:
6.61 Pounds
Solution:
Step 1: Calculate Mass of Water as;
Density = Mass ÷ Volume
Solving for Mass,
Mass = Density × Volume ------ (1)
As,
Density of Water = 1 g.cm⁻³
And,
3 L of Water = 3000 cm³
Putting values in equation 1,
Mass = 1 g.cm⁻³ × 3000 cm³
Mass = 3000 g
Step 2: Convert Grams into Pounds;
As,
1 Gram = 0.002204 Pounds
So,
3000 Grams = X Pounds
Solving for X,
X = (3000 Grams × 0.002204 Pounds) ÷ 1 Gram
X = 6.61 Pounds
Given that the volume and amount of water are kept constant,
P/T = constant
P₁/T₁ = P₂/T₂
Normal atmospheric pressure is 746 mmHg and normal boiling point of water is 100 °C.
746/100 = 589/T₂
T₂ = 79.0 °C
The color changes, heat change, smell change, are a few
Answer:
this is my old account and these still dont have answers
Explanation:
