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vekshin1
3 years ago
6

The mass number of this atom is_________​

Chemistry
1 answer:
galben [10]3 years ago
3 0

Answer:

7

Explanation:

The mass number is neutrons plus protons

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Determine the pressure change when a volume of gas at 760 mmHg is heated from 30.0 °C to 40.0 °C.
bekas [8.4K]

Answer:

<u>253.33 mmHg</u>

Explanation:

According to Charles' Law,

P₁ / T₁ = P₂ / T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂ / T₁

= 760 x 40 / 30

= 760 x 4/3

= 1013.33 mmHg

Change in Pressure

= 1013.33 - 760

= <u>253.33 mmHg</u>

5 0
2 years ago
What is the wavelength of an X-ray that has a frequency of 7.8 x 1017 Hz
SVEN [57.7K]

Answer:

λ = 0.38 ×10⁻⁹ m

Explanation:

Given data:

Wavelength of xray = ?

Frequency of xray = 7.8 ×10¹⁷ Hz

Solution:

Formula:

Speed of light = wavelength × frequency

speed of light = 3×10⁸ m/s

Now we will put the values in formula.

3×10⁸ m/s = λ × 7.8 ×10¹⁷ Hz

λ = 3×10⁸ m/s / 7.8 ×10¹⁷ Hz

         Hz = s⁻¹

λ = 3×10⁸ m/s / 7.8 ×10¹⁷s⁻¹

λ = 0.38 ×10⁻⁹ m

3 0
2 years ago
ANSWER QUICK PLEASE ILL GIVE BRAINLIEST AND 50 POINTS
yawa3891 [41]

Answer:

Single replacement and Zinc Sulfate

the 2nd one is double replacement and potassium nitrate

5 0
2 years ago
Read 2 more answers
What property can be used to determine if a sample is a pure substance or a mixture?
Yuliya22 [10]

Answer:

Melting point

Explanation:

Pure substances have sharp melting and boiling points while impurities lower the melting point and raise the boiling point

7 0
2 years ago
A compound is found to be 30.45% n and 69.55 % o by mass. if 1.63 g of this compound occupy 389 ml at 0.00°c and 775 mm hg, what
Charra [1.4K]
1) mass composition

N: 30.45%
O: 69.55%
   -----------
   100.00%

2) molar composition

Divide each element by its atomic mass

N: 30.45 / 14.00 = 2.175 mol

O: 69.55 / 16.00 = 4.346875

4) Find the smallest molar proportion

Divide both by the smaller number

N: 2.175 / 2.175 = 1

O: 4.346875 / 2.175 = 1.999 = 2

5) Empirical formula: NO2

6) mass of the empirical formula

14.00 + 2 * 16.00 = 46.00 g

7) Find the number of moles of the gas using the equation pV = nRT

=> n = pV / RT = (775/760) atm * 0.389 l / (0.0821 atm*l /K*mol * 273.15K)

=> n = 0.01769 moles

8) Find molar mass

molar mass = mass in grams / number of moles = 1.63 g / 0.01769 mol = 92.14 g / mol

9) Find how many times the mass of the empirical formula is contained in the molar mass

92.14 / 46.00 = 2.00

10) Multiply the subscripts of the empirical formula by the number found in the previous step

=> N2O4

Answer: N2O4
3 0
3 years ago
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