This is pretty simple actually :) You are going to use the equation M1xV1=M2xV2
M stands for molarity and V is volume. Plug in the information you have, and then solve for the unknown using simple algebra. You get 6.0M NaNo3 x 250mL= 15M NaNO3 x V2. Now solve for V2. Keep in mind that you will have to use stoichiometry to convert to liters instead of liters if your answer requires it. Hope this helps! :)
6.6 g
Explanation:
The mole ration between CaCO₃and CO₂ is 1 : 1
Because the molar mass of CaCO₃ is 100.0869 g/mol the amount of moles used in this chemical reaction is;
15/ 100
This will be similar to the moles of CO₂
Because the molar mass of CO₂ is 44g, then well multiply by the moles;
15/100 * 44
= 6.6 g
Answer:
930 pls mark me branilest
The volume of ideal gas that would occupy at 1.50 atm and 216 c is
2016.49 ml
<u><em>calculation</em></u>
- volume is calculated using a combined gas equation
that is P1V1/T1= P2V2/T2
P1( pressure 1) = 7.20 atm
V1 ( volume 1) = 250 ml
T1 ( temperature 1) = 18 + 273=291 K
P2 ( pressure 2) = 1.50 atm
T2 ( temperature 2)= 216+273=489 K
V2 ( volume 2) =?
- by making V2 the subject of the formula
V2=[(T2 xP1 x V1)/(T1 xP2)]
V2=[ (489 K x 7.20 atm x 250 ml) / ( 291 k x 1.50 atm)] = 2016.49 Ml
