#1)
A) b = 10.57
B) a = 22.66; the different methods are shown below.
#2)
A) Let a = the side opposite the 15° angle; a = 1.35.
Let B = the angle opposite the side marked 4; m∠B = 50.07°.
Let C = the angle opposite the side marked 3; m∠C = 114.93°.
B) b = 10.77
m∠A = 83°
a = 15.11
Explanation
#1)
A) We know that the sine ratio is opposite/hypotenuse. The side opposite the 25° angle is b, and the hypotenuse is 25:
sin 25 = b/25
Multiply both sides by 25:
25*sin 25 = (b/25)*25
25*sin 25 = b
10.57 = b
B) The first way we can find a is using the Pythagorean theorem. In Part A above, we found the length of b, the other leg of the triangle, and we know the measure of the hypotenuse:
a²+(10.57)² = 25²
a²+111.7249 = 625
Subtract 111.7249 from both sides:
a²+111.7249 - 111.7249 = 625 - 111.7249
a² = 513.2751
Take the square root of both sides:
√a² = √513.2751
a = 22.66
The second way is using the cosine ratio, adjacent/hypotenuse. Side a is adjacent to the 25° angle, and the hypotenuse is 25:
cos 25 = a/25
Multiply both sides by 25:
25*cos 25 = (a/25)*25
25*cos 25 = a
22.66 = a
The third way is using the other angle. First, find the measure of angle A by subtracting the other two angles from 180:
m∠A = 180-(90+25) = 180-115 = 65°
Side a is opposite ∠A; opposite/hypotenuse is the sine ratio:
a/25 = sin 65
Multiply both sides by 25:
(a/25)*25 = 25*sin 65
a = 25*sin 65
a = 22.66
#2)
A) Let side a be the one across from the 15° angle. This would make the 15° angle ∠A. We will define b as the side marked 4 and c as the side marked 3. We will use the law of cosines:
a² = b²+c²-2bc cos A
a² = 4²+3²-2(4)(3)cos 15
a² = 16+9-24cos 15
a² = 25-24cos 15
a² = 1.82
Take the square root of both sides:
√a² = √1.82
a = 1.35
Use the law of sines to find m∠B:
sin A/a = sin B/b
sin 15/1.35 = sin B/4
Cross multiply:
4*sin 15 = 1.35*sin B
Divide both sides by 1.35:
(4*sin 15)/1.35 = (1.35*sin B)/1.35
(4*sin 15)/1.35 = sin B
Take the inverse sine of both sides:
sin⁻¹((4*sin 15)/1.35) = sin⁻¹(sin B)
50.07 = B
Subtract both known angles from 180 to find m∠C:
180-(15+50.07) = 180-65.07 = 114.93°
B) Use the law of sines to find side b:
sin C/c = sin B/b
sin 52/12 = sin 45/b
Cross multiply:
b*sin 52 = 12*sin 45
Divide both sides by sin 52:
(b*sin 52)/(sin 52) = (12*sin 45)/(sin 52)
b = 10.77
Find m∠A by subtracting both known angles from 180:
180-(52+45) = 180-97 = 83°
Use the law of sines to find side a:
sin C/c = sin A/a
sin 52/12 = sin 83/a
Cross multiply:
a*sin 52 = 12*sin 83
Divide both sides by sin 52:
(a*sin 52)/(sin 52) = (12*sin 83)/(sin 52)
a = 15.11
These quantities are related linearly with slope
3/2. without knowing the answer choices I can only give you examples of equations that fit
y-2=3/2(x-2). or y=3/2(x) -1
etc
Step-by-step explanation:
Hey there!
The amount deposited= $1800
And it's just 20% of total monthly amount.
Let total amount be "x".
Then;
$1800 = 20% of X

or, 180000= 20x
or, X = 180000=/20
Therefore, total monthly amount or income was $9000.
<u>Hope </u><u>it </u><u>helps!</u>
Answer:
<h3>46.</h3>
<u>Total number in favour:</u>
<u>Probability:</u>
- P(favour, A) = 128/224 = 4/7
<h3>47.</h3>
<u>Total number in against:</u>
<u>Probability:</u>
- P(against, not B) = 32/80 = 2/5
We can conclude that the value of x is (∠MNP + 66)/8 and angle m∠RNM = ∠RNQ - ∠MNP + 78.
<h3>
What are angles?</h3>
- An angle is a figure in Euclidean geometry formed by two rays, called the sides of the angle, that share a common endpoint, called the vertex of the angle.
- Angles formed by two rays are located in the plane containing the rays.
- Angles are also formed when two planes intersect.
- These are known as dihedral angles.
So,
- ∠MNQ = ∠MNP + ∠PNQ
- 8x + 12 = ∠MNP + 78
- 8x + 12 - 78 = ∠MNP
- 8x - 66 = ∠MNP
- 8x = ∠MNP + 66
- x = (∠MNP + 66)/8
Now, substitute 'x = (∠MNP + 66)/8' in 8x + 12:
- ∠MNQ = 8x + 12
- ∠MNQ = 8 ×(∠MNP + 66)/8 + 12
- ∠MNQ = ∠MNP + 66 + 12
- ∠MNQ = ∠MNP + 78
Hence, m∠RNM = ∠RNQ - ∠MNP + 78
Therefore, in the given question value of x is (∠MNP + 66)/8 and angle m∠RNM = ∠RNQ - ∠MNP + 78.
Know more about angles here:
brainly.com/question/25716982
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