All categories

3 years ago

X <-4 graphed as an inequality on a number line

1 answer:

7 0

See it is < and not ≤ so we don't include -4

put a circle around -4 but don't shade it in
to get there, move 4 units left from 0

then we see x is less than -4
so shade to the left of the circle

You might be interested in

What is the slope of the line that passes through (5,-2) and (-3,4)

kolezko [41]

Answer:

Slope = $\frac{-3}{4}$

Step-by-step explanation:

(5 , -2) ; (-3, 4)

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{4-[-2]}{-3-5}\\\\=\frac{4+2}{-3-5}\\\\=\frac{6}{-8}\\\\=\frac{-3}{4}\\\\$

3 0

3 years ago

Math workshops and final exams: The college tutoring center staff are considering whether the center should increase the number

ludmilkaskok [199]

Answer:

2. Number of workshops attended.

Step-by-step explanation:

The variable of interest for predicting the final exam score and doing regression analysis is workshop attendance. Therefore, the response variable should be the number of workshops attended by each student.

This also agrees with what the college tutoring center staff are considering, which forms the research question: "should the center increase the number of math workshops they offer to help students improve their performance in math classes?"

3 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

San Jose's elevation is 87 feet. Salton City's elevation is -125 feet. Jackie claims that Salton

joja [24]

Answer:

Third option

Step-by-step explanation:

Please help me by marking me brainliest. I'm one away :)

7 0

3 years ago

The region R enclosed between the graph of the function y=x^2−4x+5 and the x-axis for 0≤x≤4 is partitioned into four subinterval

Marina CMI [18]

Answer:

9.00 square units

Step-by-step explanation:

The width of the interval is 4 − 0 = 4. Divided by 4 equal subintervals, the width of each subinterval is 4/4 = 1.

The subintervals are:

0 ≤ x ≤ 1

1 ≤ x ≤ 2

2 ≤ x ≤ 3

3 ≤ x ≤ 4

MRAM is midpoint rectangular approximation method. So we use the midpoints of each interval to find the height of the rectangle:

f(0.5) = (0.5)² − 4(0.5) + 5 = 3.25

f(1.5) = (1.5)² − 4(1.5) + 5 = 1.25

f(2.5) = (2.5)² − 4(2.5) + 5 = 1.25

f(3.5) = (3.5)² − 4(3.5) + 5 = 3.25

So the total approximate area is:

A = 3.25 + 1.25 + 1.25 + 3.25

A = 9.00

Graph: desmos.com/calculator/x8dcibqszo

7 0

3 years ago

Read 2 more answers