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FromTheMoon [43]
3 years ago
13

Explain how a(b + c ) can rewritten as (b + c) and as ba + ca

Mathematics
1 answer:
mart [117]3 years ago
5 0

Answer:

The distributive property makes it possible

Step-by-step explanation:

Step one:

given the expression a(b + c )

the first step is to open the bracket, that is multiply all the terms in the bracket by a, so multiply b by a and c by a also.

Step two:

Thus, this property is called the distributive property of multiplication

a*b+ca

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Please help me answer it right
kupik [55]

Answer: B

Step-by-step explanation:

3/4 x 4/4 = 12/16

3 0
3 years ago
Read 2 more answers
A. y = - 1/4x +9
Vikentia [17]
It's B= 1/4x+6 because I solve it
6 0
3 years ago
For each equation, find y when x=-3. Then find x when y = 2<br> 1. y = 6x + 8
crimeas [40]

<u><em>⬇ Hey, the answer is down below! :) ⬇</em></u>

<u><em>For y:</em></u> x = -3

For y it stays the same.

<u><em>For x:</em></u> y = 2

For x it stays the same too.

<u><em>For 1.):</em></u> x = \frac{1}{6}y + \frac{-4}{3}

Step-by-step explanation:

<u><em>For y there is no step-by-step explanation unfortunately.</em></u>

<u><em>For x there isn't a step-by-step explanation too unfortunately.</em></u>

<u><em>⬇ For 1.) there is a step-by-step explanation! ⬇</em></u>

For step 1 we should flip the equations.

6x + 8 = y

For step 2 we should add -8 to both sides.

6x + 8 + − 8 = y + −8

= 6x = y − 8

For step 3 we should divide both sides by 6.

\frac{6x}{6} = \frac{y - 8}{6}

= x = x = \frac{1}{6}y + \frac{-4}{3}

<u><em>In result we should have</em></u> x = \frac{1}{6}y + \frac{-4}{3} <u><em>as the answer!</em></u>

7 0
3 years ago
Which number is rational -3 1/2, sqrt 5, pi, 9.23157...
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-3 1/2 is rational because the decimal ends at -3.5. It is not sqrt(5) because the decimal never ends and the same follows for pi and 9.23157.


7 0
3 years ago
Read 2 more answers
What additional piece of information do we need to prove that MLN ≅ OPN
mote1985 [20]

Answer:

N is the midpoint of MO

Step-by-step explanation:

Given

See attachment for triangles

Required

Additional information to prove MLN \cong OPN

From the attachment, we already have:

LM \simeq OP and LN \simeq ON

The additional information that must be true for MLN \cong OPN  to be true is: <em>N is the midpoint of MO</em>

Because this piece of information proves that:

MN \simeq ON

<em>Which in other words makes </em>MLN \cong OPN<em> </em>

6 0
3 years ago
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