Vertex form is y=a(x-h)^2+k, so we can rearrange to that form...
y=3x^2-6x+2 subtract 2 from both sides
y-2=3x^2-6x divide both sides by 3
(y-2)/3=x^2-2x, halve the linear coefficient, square it, add it to both sides...in this case: (-2/2)^2=1 so
(y-2)/3+1=x^2-2x+1 now the right side is a perfect square
(y-2+3)/3=(x-1)^2
(y+1)/3=(x-1)^2 multiply both sides by 3
y+1=3(x-1)^2 subtract 1 from both sides
y=3(x-1)^2-1 so the vertex is:
(1, -1)
...
Now if you'd like you can commit to memory the vertex point for any parabola so you don't have to do the calculations like what we did above. The vertex of any quadratic (parabola), ax^2+bx+c is:
x= -b/(2a), y= (4ac-b^2)/(4a)
Then you will always be able to do a quick calculation of the vertex :)
Answer:
(x-8y)(x-8y)
Step-by-step explanation:
write the expression as a product with the factors x and 8y
8^2 -2(x)8y+64y^2
multiply terms with equal exponents by multiplying the bases
x^2 -2 (x) 8y + (8y)^2
factor
(x-8y)^2 which is equal to c
Answer: $10.90
Step-by-step explanation:
Skittles-1.44
M&M's-3.744
Pretzels-5.72
Not sure if its a typo, thats if theres 3.12lbs of of M&M's
The answer is theres 312 M&M's is 374.4
Answer:
Please check the explanation.
Step-by-step explanation:
Given the function
Putting all the values of y=9, 6, 0, and -3 to complete the table
FOR y=9
putting y=9
switch sides
subtract 3 from both sides
Hence,
when y=9, x=4
FOR y=6
putting y=6
switch sides
subtract 3 from both sides
Hence,
when y=6, x=2
FOR y=0
putting y=0
switch sides
subtract 3 from both sides
Hence,
when y=0, x=-2
FOR y=-3
putting y=-3
switch sides
subtract 3 from both sides
Hence,
when y=-3, x=-4
Hence, the table becomes:
x y
9 4
6 2
0 -2
-3 -4
