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inna [77]
3 years ago
8

If x=-6, which inequality is true ??​

Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0

<em>Answer:</em>

The inequality that is true is -5 - 3x > 10.

<em>Step-by-step explanation:</em>

if x = -6

we can subtitution x to every inequality, so :

-5 - 3x > 10

-5 - 3(-6) > 10

-5 - (-18) > 10

-5 + 18 > 10

13 > 10 [true]

-3 - 5x < -14

-3 - 5(-6) < -14

-3 - (-30) < -14

-3 + 30 < -14

27 < -14 [false]

2 - x < -3

2 - (-6) < -3

2 + 6 < -3

8 < -3 [false]

So if x=-6, inequality true is -5 - 3x > 10.

<em>If this was helpful, please mark brainliest. Have a beautiful day. </em>

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<h3>Answer:  5 cakes</h3>

================================================

Explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.

a \frac{b}{c} = \frac{a*c+b}{c}\\\\12 \frac{1}{4} = \frac{12*4+1}{4}\\\\12 \frac{1}{4} = \frac{49}{4}\\\\

Do the same for the other mixed number 2 & 1/3.

a \frac{b}{c} = \frac{a*c+b}{c}\\\\2 \frac{1}{3} = \frac{2*3+1}{3}\\\\2 \frac{1}{3} = \frac{7}{3}\\\\

-----------------------

From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.

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\frac{21}{4} = \frac{4*5+1}{4}\\\\\frac{21}{4} = \frac{4*5}{4}+\frac{1}{4}\\\\\frac{21}{4} = 4+\frac{1}{4}\\\\\frac{21}{4} = 5 \frac{1}{4}\\\\

Note that 21/4 = 5.25 and 1/4 = 0.25 to help check the answer.

-----------------------

Therefore, she can make 5 cakes. The fractional portion 1/4 is ignored since we're only considering whole cakes rather than partial ones.

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