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Lisa [10]
4 years ago
12

Which is not an appearance of a solution?

Physics
1 answer:
iren [92.7K]4 years ago
6 0

Answer:

A i think but i could be wrong

Explanation:

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Scientific notation is a method of expressing very small and very large numbers *<br><br> yes<br> No
mars1129 [50]
The answer is yes:)
Scientific notation is the expression of a number in the form of x * 10^x
4 0
4 years ago
Consider a helium balloon on a string tied to the seat of your stationary car. The windows are closed, so there is no air motion
timama [110]

Answer:

The balloon will move forward.

The density of the air will be greater at the back of the balloon; similar

to the density of air being greater at lower altitudes due to gravitational

attraction because of the weight of the air in an air column.

A block of wood in water rises because of the difference in pressures

on the top and bottom of the block.

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3 years ago
Most of the mass of an element is found in the?
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Most of the mass of an element is found in the NUCLEUS
6 0
4 years ago
g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr
Lorico [155]

To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

a = \frac{GM}{r^2}

Where

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius of Earth

This equation can be differentiated with respect to the radius of change, that is

\frac{da}{dr} = -2\frac{GM}{r^3}

da = -2\frac{GM}{r^3}dr

At the same time since Newton's second law we know that:

F_w = ma

Where,

m = mass

a =Acceleration

From the previous value given for acceleration we have to

F_W = m (\frac{GM}{r^2} ) = 600N

Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:

dF_W = mda

dF_W = m(-2\frac{GM}{r^3}dr)

dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})

dF_W = -2F_W(\frac{dr}{r})

But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:

dF_W = -2(600)(\frac{1.6*10^3}{6.37*10^6})

dF_W = -0.3N

Therefore there is a weight loss of 0.3N every kilometer.

4 0
4 years ago
PLEASE help its timed..
mojhsa [17]

Answer:

D

Explanation:

by increasing the distance through which force is applied, by changing the direction of force applied or by multiplying force of speed of the energy applied

3 0
3 years ago
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