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natali 33 [55]
3 years ago
12

The Eiffel tower in Paris is 300 meters tall on a cold day (T = -24 degrees Celsius), what is its height on a hot day when the t

emperature is 35 degrees? (It is made of iron which has a coefficient of linear expansion of 0.000012 per degree Celsius.)
Physics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer:

Length of Eiffel tower, when the temperature is 35 degrees = 300.21 m

Explanation:

Thermal expansion is given by the expression

\Delta L=L\alpha \Delta T \\

Here length of Eiffel tower, L = 300 m

Coefficient of thermal expansion, α = 0.000012 per degree Celsius

Change in temperature, = 35 - (-24) = 59degrees Celsius

Substituting

\Delta L=L\alpha \Delta T= 300\times 0.000012\times 59=0.2124m \\

Length of Eiffel tower, when the temperature is 35 degrees = 300 + 0.2124 = 300.21 m

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I <em>E </em>I  = \sqrt{(7.89e5)^{2}  + (7.89e5)^{2}} =  1.242e6\frac{N}{C}

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Thus for (a) net magnitude =  1.115e6\frac{N}{C} @ 45° above +x axis

for situation (b)

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E₊₄(x) = K(q/d²) = (8.99e9)× ((4.0e-6)÷(5.7e-2)) = 6.30e5(+x)

 E₊₁(y) = K(q/d²) = (8.99e9)× ((1.0e-6)÷(5.7e-2)) = 1.58e5(-y)

E₋₁(x) = K(q/d²) = (8.99e9)× ((1.0e-6)÷(5.7e-2)) = 1.58e5(+x)

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E = E₊₄ + E₊₁ + E₋₁ + E₊₆

= 6.30e5(x) - 1.58e5(y) + 1.58e5(x) + 9.46e5(y)

= 7.88e5(x) + 7.88e5(y)

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Thus for (a) and (b) the net magnitude =  1.242e6\frac{N}{C} @ 45° above +x axis

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