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professor190 [17]
4 years ago
5

A camper dives from the edge of a swimming pool at water level with a speed of 8.0 m/s at an angle of 30.0° above the horizontal

. (a) How long is the diver in the air? (b) How high is the diver in the air? (c)How far out in the pool does the diver land?
Physics
1 answer:
adoni [48]4 years ago
8 0

Answer:

(a) 0.816 s

(b) 0.816 m

(c) 5.656 m

Explanation:

u = 8 m/s, theta = 30 degree,

(a) Use the formula for time of flight

T = 2 u Sin theta / g

T = ( 2 x 8 x Sin 30 ) / 9.8 = 0.816 s

(b) Use the formula for maximum height

H = u^2 Sin^2theta / 2 g

H = ( 8 x 8 x Sin^2 30) / ( 2 x 9.8)

H = 0.816 m

(c) Use the formula for horizontal range

R = u^2 Sin 2 theta / g

R = ( 8 x 8 x Sin 60) / 9.8

R = 5.656 m

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Tom [10]

Answer:

B. +m

Explanation:

The magnification of an image is defined as the ratio between the size of the image and of the object:

m = \frac{y'}{y}

where we have

y' = size of the image

y = size of the object

There are two possible situations:

- When m is positive, y' has same sign as y: this means that the image image is upright

- When m is negative, y' has opposite sign to y: this means that the image is upside down

Therefore, the correct option representing an upright image is

B. +m

5 0
3 years ago
Consider two planets of mass m and 2m,
Rzqust [24]

Answer:

Part a)

\frac{F_1}{F_2} = 10.125

Part b)

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

\frac{T_1}{T_2} = 9.54

Explanation:

Part a)

As we know that the gravitational force is given as

F = \frac{GMm}{r^2}

so we will have to find the ratio of force on two planets due to star

so here we have

\frac{F_1}{F_2} = \frac{m_1r_2^2}{m_2r_1^2}

\frac{F_1}{F_2} = \frac{m (4.5r)^2}{(2m) r}

\frac{F_1}{F_2} = 10.125

Part b)

Orbital speed is given as

v = \sqrt{\frac{GM}{r}}

so the ratio of two orbital speed is given as

\frac{v_1}{v_2} = \frac{r_2}{r_1}

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

Time period is given as

T = 2\pi\sqrt{\frac{r^3}{GM}}

so the ratio of two time period is given as

\frac{T_1}{T_2} = \sqrt{\frac{r_1^3}{r_2^3}}

\frac{T_1}{T_2} = \sqrt{\frac{4.5r^3}{r^3}}

\frac{T_1}{T_2} = 9.54

8 0
3 years ago
Read 2 more answers
An electric generator converts kinetic energy into which kind of energy?
dem82 [27]

Answer:

Electrical Energy

Explanation:

An electric generator is a device that changes kinetic energy to electrical energy through electromagnetic induction. Electromagnetic induction is the process of generating electric current with a magnetic field. ... Because the coil is rotating in a magnetic field, electric current is generated in the wire.

8 0
4 years ago
A thin, horizontal square copper plate has a length of 6.35cm and is charged with 2.56 × 108 electrons. If the electrons are uni
Strike441 [17]
This is either a trick question or a very hard one. In the first case: An electric field cannot occur inside a conductor (or by using the superposition principle you find out that at this point your electric fields cancel each other out)... Or you must use the laplace equation and proper boundary conditions to solve for the electrostatic potential 

<span>Edit: Considering the center of mass of the plate is on the plate</span>
5 0
3 years ago
a uniform rod of length 1.5m is placed over a wedge at 0.5m from one end .a force of 100 N is applied at its one end near the we
andreev551 [17]

Explanation:

The rod is uniform, so the center of gravity is at the center, or 0.75 m from the end.  The wedge is 0.5 m from the end, so the center is 0.25 m from the wedge.

Sum the torques about the wedge (it may help to draw a diagram first).  Take counterclockwise to be positive.

∑τ = Iα

W (0.25 m) − (100 N) (0.50 m) = 0

W = 200 N

Sum the forces in the y direction.

∑F = ma

F − 100 N − 200 N = 0

F = 300 N

8 0
3 years ago
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