In the Haber process, nitrogen (N2) and hydrogen (H2) are directly combined to form ammonia (NH3). Which illustration contains t
he stoichiometric quantities of the reactants for this reaction?
1 answer:
The following illustration <span>contains the stoichiometric quantities of the reactants for this reaction.
</span><span>In the Haber process, nitrogen (N2) and hydrogen (H2) are directly combined to form ammonia (NH3). </span><span>The reaction is as follows :
N</span>
+ 
= 
Therefore, 1 mole of nitrogen is equivalent to 3 moles of Hydrogen
</span><span>In the Haber process, nitrogen (N2) and hydrogen (H2) are directly combined to form ammonia (NH3). </span><span>The reaction is as follows :
N</span>
Therefore, 1 mole of nitrogen is equivalent to 3 moles of Hydrogen
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8.1moles
Explanation:
Given parameters:
Mass of water to be decomposed = 29.2g
Unknown:
Number of moles of oxygen.
Solution:
To solve this problem, we first write the balanced reaction equation :
2H₂O → 2H₂ + O₂
Now convert the given mass of the water to number of moles;
Number of moles of water =
Molar mass of water = 2(1) + 16 = 18g/mol
Number of moles of water = = 16.2moles
From the balanced reaction equation:
2 moles of water produced 1 mole of oxygen gas;
16.2 mole of water will produce = 8.1moles of oxygen gas
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Number of moles brainly.com/question/1841136
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