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sineoko [7]
3 years ago
6

How do large food particles enter an amoeba

Chemistry
1 answer:
scoundrel [369]3 years ago
7 0
Phagocytosis, the amoeba surrounds the food particle and engulfs it. Then it's stored for when the cell needs food.
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You know that 8.9 moles of solute particles are dissolved in that liquid solution. If the molarity of the solution is 25 M, how
pychu [463]

Answer:

V = 0.356 L

Explanation:

In this case, we need to use the following expression:

M = n/V (1)

Where:

M: molarity of solution (mol/L or M)

n: moles of solute (moles)

V: Volume of solution (Liters)

From these expression, we can solve for V:

V = n/M  (2)

Now, replacing the given data we can solve V:

V = 8.9 / 25

V = 0.356 L

5 0
3 years ago
. If the half-life of cesium-133 is 30 years, how much of a 600g sample of cesium-133 will be left after
e-lub [12.9K]

Answer:

Caesium (55Cs) has 40 known isotopes, making it, along with barium and mercury, one of the elements with the most isotopes. The atomic masses of these isotopes range from 112 to 151. Only one isotope, 133Cs, is stable. The longest-lived radioisotopes are 135Cs with a half-life of 2.3 million years, ... It constitutes most of the radioactivity still left from the Chernobyl accident ...

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2 years ago
This is called ____________when pressure builds up until gasses can no longer escape this substance destroys everything in its p
horsena [70]
Volcanoes can destroy each and every thing
7 0
2 years ago
A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:
hodyreva [135]

Answer:

-252.5 kJ/mol = ΔH H2O(g)

Explanation:

ΔH Fe2O3 = -825.5kJ/mol

ΔH H2 = 0kJ/mol

ΔH Fe = 0kJ/mol

Based on Hess's law, ΔH of a reaction is the sum of ΔH of products - ΔH of reactants. For the reaction:

Fe2O3(s) + 3 H2(g) →2Fe(s) + 3 H2O(g)

ΔHr = 67.9kJ/mol = 3*ΔH H2O + 2*ΔHFe - (ΔH Fe2O3 + 3*Δ H2)

67.9kJ/mol = 3*ΔH H2O + 2*0kJ/mol - (ΔH -825.5kJ/mol + 3*Δ H2)

67.9 = 3*ΔH H2O(g) + 825.5kJ/mol

-757.6kJ/mol = 3*ΔH H2O(g)

<h3>-252.5 kJ/mol = ΔH H2O(g)</h3>
6 0
2 years ago
Calculate the grams of solute required to make 250 g of a 0.20% MgSO4?
Kisachek [45]
.. it’s the answer 0.25 g MgSO4? ..
I may be wrong.
5 0
3 years ago
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