All categories

3 years ago

As waves get closer to a beach they:

Physics

1 answer:

hoa [83]3 years ago

3 0

Answer:

As waves get closer to a beach they decrease in height.

Explanation:

As a wave crest approaches the shoreline, it is usual that one end of the line is closer to the shoreline than the other. The implication of this is that the energy in a wave is also spread over quite a larger area,this in turn reduces the height of the waves. In other words, refraction often makes waves smaller.

Waves are caused by wind. Wave height in the open ocean is determined by three factors. The greater the wind speed the larger the waves. The greater the duration of the wind (or storm) the larger the waves. The greater the fetch (area over which the wind is blowing - size of storm) the larger the waves.

You might be interested in

Find the Kinetic Energy of a trailer of mass 30,000 kg moving at a Speed of 60 km/h

olasank [31]

Explanation: Formulas you need to use:

K=0.5mass(Velocity^2)

km/h / 3.6 ===>M/S

Step 1:

convert km/h to m/s

Put the values in the formula :

3 0

3 years ago

Suppose that during any period of ¼ second there is one instant at which the crests or troughs of component waves are exactly in

kolezko [41]

<h3>Answer;</h3>

A. 4

<h3>Explanation;</h3>

The period of a wave or periodic time is the time taken for a complete oscillation to occur. For example its is the time taken between two successive crests or troughs.
The beats or oscillation that occur in one second represents the frequency. Frequency is the number of complete oscillations or beats in one second in a wave.
Frequency, measured in Hertz is given by the reciprocal of the periodic time.
Thus; Frequency or beats per second = 1/(1/4) = 4
Hence , 4 beats per second

6 0

4 years ago

labwork [276]

Answer:

D. protons and neutrons

3 0

3 years ago

Read 2 more answers

Which scientist was the first to propose the heliocentric model of the universe

andreyandreev [35.5K]

Hi there! :D

Which scientist was the first to propose the heliocentric model of the universe

$Copernicus$

6 0

3 years ago

Read 2 more answers

Consider a neutron star of radius 10 km that spins with a period of 0.8 seconds. Imagine a person is standing at the equator of

Arada [10]

Answer:

a = 616850.28 m/s²

Explanation:

Given that,

The radius of the neutron star, r = 10 Km

= 10,000 m

The time period of the neutron star, T = 0.8 s

The centripetal acceleration is given by the formula,

a = v²/r

The linear velocity is given by the relation,

v = rω

The time taken to complete one complete rotation is given by the relation

T = 2π /ω

Where,

ω = 2π / T

Substituting v and ω into the equation for centripetal acceleration. It becomes

a = 4π²r/T²

Substituting the given values in the above equation

a = 4π² x 10000 / 0.8²

= 616850.28 m/s²

Hence, the centripetal acceleration of this person is, a = 616850.28 m/s²

8 0

3 years ago