Answer:
<em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>use</em><em> </em><em>formula</em><em> </em><em>of</em><em> </em><em>volume</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>volume</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>cuboid</em><em>.</em><em> </em><em>(</em><em> </em><em>i.e</em><em> </em><em>v</em><em> </em><em>=</em><em> </em><em>l</em><em> </em><em>×</em><em>b</em><em> </em><em>×</em><em>h</em><em>)</em>
Explanation:
here, let your length of cuboid be x cm, breadth be y cm and height be z cm .
now, formula to find volume of cuboid = length ×
breadth × height.
so, v( volume)= l (length)× b (breadth)× h (height)
or, v= x cm × y cm × z cm
therefore, volume is xyz cm^3..... answer.
<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
38 N, 40.0° below the horizontal
Explanation:
Force exerted by an object equals mass times acceleration of that object: F = m ⨉ a. To use this formula, you need to use SI units: Newtons for force, kilograms for mass, and meters per second squared for acceleration.
Potential energy is measured by mass * gravity * height. So, the larger the mass on a roller coaster, the more potential energy it has.
Also, the higher it is, the more potential energy it has.
Answer:
K_{total} = 19.4 J
Explanation:
The total kinetic energy that is formed by the linear part and the rotational part is requested

let's look for each energy
linear
= ½ m v²
rotation
= ½ I w²
the moment of inertia of a solid sphere is
I = 2/5 m r²
we substitute
= ½ mv² + ½ I w²
angular and linear velocity are related
v = w r
we substitute
K_{total} = ½ m w² r² + ½ (2/5 m r²) w²
K_{total} = m w² r² (½ + 1/5)
K_{total} =
m w² r²
let's calculate
K_{total} =
6.40 16.0² 0.130²
K_{total} = 19.4 J
Answer:
292.3254055 W/m²
469.26267 V/m

Explanation:
P = Power of bulb = 90 W
d = Diameter of bulb = 7 cm
r = Radius = 
= Permittivity of free space = 
c = Speed of light = 
The intensity is given by

5% of this energy goes to the visible light so the intensity is

The visible light intensity at the surface of the bulb is 292.3254055 W/m²
Energy density of the wave is

Energy density is also given by

The amplitude of the electric field at this surface is 469.26267 V/m
Amplitude of a magnetic field is given by

The amplitude of the magnetic field at this surface is 