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3 years ago

What is the answer to – 5m (6m2-8m)

Mathematics

1 answer:

dexar [7]3 years ago

7 0

Answer:

-20m^2

Step-by-step explanation:

-5m (6m x 2 - 8m)

-5m (12m-8m)

-5m x 4m

=-20m^2

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Line 2x-4y-7=0 meets the x axis at point (k,0). Find the value of k

kolbaska11 [484]

K=4
add seven on both sides
2x-4y=7
add 4y on both sides
2x=7+4y
divide 2 on both sides
x=7+4y/2
plug that into original equation
2(7+4y/2)-4y-7=0
7 and 4y cancel out
2(2)=0
4=0

4 0

3 years ago

Can someone help, please?

Sunny_sXe [5.5K]

You have to first mess around with the first shape, ABCD, and split that into a rectangle and a right triangle. once you do that, it's pretty painstaking, but simple.

if you look at it you can tell that EFGH is just half the size, but the same ratios and everything.

So, you would just take every perimeter measurement from ABCD, and divide it by two and then sum them together.

2.5 + 1.5 + 4.0 + 2.0 = 10

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3 years ago

Which situation below correctly represents the algebraic expression 4 + 5g? A. Nikki has 4 sticks of gum and Breanne has 5 times

zhenek [66]

Answer:

Step-by-step explanation:

The 4 is the base price. Paying 5g or $5 per game is the add on

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3 years ago

A necklace costs a store owner $125 to purchase.The owner marks up the price 65%.What is the selling price of the necklace.

solniwko [45]

The necklace costs 206.25

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3 years ago

Read 2 more answers

sons in the NHL,nts than anyone whoccomplished thiser games thanHer. Here are theRg each season:74, 45, 81, 48, 80,Working for a

vesna_86 [32]

Step 1:

In descriptive statistics, a box plot or boxplot (also known as box and whisker plot) is a type of chart often used in explanatory data analysis. Box plots visually show the distribution of numerical data and skewness through displaying the data quartiles (or percentiles) and averages.

Step 2:

To sketch a boxplot, you will need to determine the following:

Minimum

Lower quartile

Median

Upper quartile

Maximum

Step 3:

USA

First arrange the data from the least to the greatest.

14 , 26, 33, 34, 35, 38, 40, 41, 44, 46, 46, 49, 53, 66, 70.

Minimum = 14

$\begin{gathered} \text{Lower quartile position = }\frac{1}{4}(n+1)^{th} \\ \text{= }\frac{15+1}{4}\text{ = }\frac{16}{4}=4^{th} \\ Q_1\text{ = lower quartile = 34} \end{gathered}$

Median = 41

$\begin{gathered} \text{Upper quartile position = }\frac{3}{4}(n+1)^{th} \\ =\text{ }\frac{3\text{ }\times(15+1)}{4} \\ =12^{th} \\ Q_3\text{ = upper quartile = 49} \end{gathered}$

Maximum = 70

Interquartile range IQR = 49 - 34 = 15

Canada

22, 28, 31, 31, 35, 35, 36, 39, 40, 40, 42, 49, 53, 63, 68

Minimum = 22