Um 12 i think dat really look hard
1. 5x + 6 = 2 + 3x
-3x. - 3x
-------------------------
2x + 6 = 2
- 6. - 6
-------------------------
2x = -4
---- -----
2. 2
x = -2
2. 2(6 -2y) = -1(4y-9)
12 -4y = -4y + 9
+4y. +4y
----------------------------
.12 /=\ 9
No solution
3. 2z-6 = 2(z+2) + 10
2z -6 = 2z + 4 + 10
2z -6 = 2z +14
-2z. -2z
-6 /=\ 14
No solution.
Answer:
$6.45
Step-by-step explanation:
$21.50-$15.05=$6.45
Answer:
Step-by-step explanation:
Let, 
= y
sin(y) = 
---------(1)
cos(y) = 
= 
= 
Therefore, from equation (1),
Or ![\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7Bx%7D%7B6%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7Bx%5E2%7D%7B36%7D%7D%7D)
At x = 4,
![\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7B4%7D%7B6%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7B4%5E2%7D%7B36%7D%7D%7D)
![\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7B2%7D%7B3%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7B16%7D%7B36%7D%7D%7D)
The range of the function is all real number values of y except y = 0.
Ordered pairs in the graph includes (-4, -0.5), (-2, -1), (-1, -2), (1, 2)
