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3 years ago

Data may be classified by one of the four levels of measurement. What is the name of the lowest level?

Mathematics

1 answer:

coldgirl [10]3 years ago

5 0

Answer:

Nominal

Step-by-step explanation:

There are four levels of measurement of data listed below in increasing order:

Nominal

Ordinal

Interval

Ratio

The nominal level of measurement is the lowest level that deals with names, categories and labels. It is a qualitative expression of data e.g Colors of eyes, yes or no responses to a survey, and favorite breakfast cereal all deal with the nominal level of measurement.

Data at this level can't be ordered in a meaningful way, and it makes no sense to calculate things such as means and standard deviations.

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The present above is a 10 in by 10 in by 10 in cube. How many square inches of wrapping paper do you need to wrap the box?

Mashutka [201]

Answer:

600 in^2.

Step-by-step explanation:

There are 6 faces on a cube so the area we need is:

6 * 10 * 10

= 600 in^2.

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3 years ago

Order the following form least to greatest: 0.07, 0.71, 0.007, 0.071?

IrinaK [193]

0.007, 0.07, 0.071, 0.71

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3 years ago

Read 2 more answers

Jose purchased 4/9 pound of peanut and 7/11 pounds of raisins find the total weight of his purchase

azamat

Answer:

The total weight of his purchase is 1.08 pounds

Step-by-step explanation:

To find the total weight of his purchase, we sum the weight of each of his purchases.

He purchased:

4/9 pound of peanut.

7/11 pounds of raisins

Total:

The least common multiple between 9 and 11 is 99.

Then

$\frac{4}{9} + \frac{7}{11} = \frac{11*4 + 9*7}{99} = \frac{107}{99} = 1.08$

The total weight of his purchase is 1.08 pounds

8 0

3 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

Solve for x: -1/2(-4+2x) = -6 - 4x

antiseptic1488 [7]

$-\dfrac{1}{2}(-4+2x)=-6-4x\ \ \ \ \ |multiply\ both\ sides\ by\ (-2)\\\\-4+2x=12+8x\ \ \ \ |add\ 4\ to\ both\ sides\\\\2x=16+8x\ \ \ \ \ |subtract\ 8x\ from\ both\ sides\\\\-6x=16\ \ \ \ \ |divide\ both\ sides\ by\ (-6)\\\\x=-\dfrac{16}{6}\\\\x=-\dfrac{8}{3}\\\\\boxed{x=-2\frac{2}{3}}$

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3 years ago