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Gelneren [198K]
3 years ago
14

URGENT!!! Please answer ASAP with full working out thank you

Mathematics
1 answer:
Tema [17]3 years ago
6 0

Step-by-step explanation:

a) \\  \frac{a}{x - 1}  -  \frac{2}{x + 1}  =  \frac{4}{(x - 1)(x + 1)}  \\  \\  \frac{a(x + 1) - 2(x - 1)}{(x  -  1)(x + 1)} =  \frac{4}{(x - 1)(x + 1)}  \\  \\ a(x + 1) - 2x + 2 = 4 \\  \\ a(x + 1) = 4 + 2x - 2 \\  \\ a(x + 1) = 2x + 2 \\  \\ a (x + 1) = 2(x + 1) \\  \\ a= \frac{2(x + 1)}{(x + 1)}  \\  \\  \huge \red{ \boxed{a = 2}}

Solve b part yourself in the same way.

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Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time he will use the Same amount of plan
DanielleElmas [232]

Answer:

3 7/12 kg

He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time

Step-by-step explanation:

On sunday , sheldon bought 4 1/2 kg of plant food. He uses 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plants. b. Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will be need? Does he have enough left to do so.

Total plant bought = 4 1/2 kg

Strawberry = 1 2/3 kg

Tomato = 1/4 kg

Strawberry + tomato

= 1 2/3 + 1/4

= 5/3 + 1/4

= 20+3/12

= 23/12 kg

Total remaining after Sunday

= Total - used

= 4 1/2 - 23/12

= 9/2 - 23/12

= 54-23/12

= 31/12

= 2 7/12 kg

Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time.

Strawberry = 2 × 1 2/3

= 2 × 5/3

= 10/3 kg

Tomato = 1 × 1/4

= 1/4 kg

Total plant needed to feed strawberry two more times and tomato 1 more time

= 10/3 kg + 1/4 kg

= 40+3/12

= 43/12 kg

= 3 7/12 kg

He will need 3 7/12 kg of plant

He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time

3 0
3 years ago
Find the area. Use 3.14 for the value of . Round your π answer. when the radius is 20ft?
lys-0071 [83]

Answer:

1256.64ft squared.

8 0
3 years ago
A stereo system is being installed in a room with a rectangular floor measuring 19 feet by 12 feet and a 7​-foot ceiling. The st
krek1111 [17]

Answer:

The shortest length of wire that can be used is 29.47 ft.

Step-by-step explanation:

To solve this problem we can follow the following steps:

1) We have the dimensions of the floor of the room. The shortest distance between its opposite corners is the diagonal. We calculate the diagonal using the Pythagorean theorem.

L = \sqrt{12^2 + 19^2}\\\\L= 22.47\ ft

2) Since the speaker is on the ceiling, and the amplifier is on the floor, then 7 more feet of wire is needed to reach the speaker. <em>Observe the attached image</em>

3) The final distance (d) is:

d = 22.47\ ft + 7\ ft\\\\d = 29.47\ ft

6 0
3 years ago
7/x+2 + 3x-4/x2+5x+6=9
larisa [96]

Answer:

is this in graph or equation? ???

4 0
3 years ago
What are the two conditions that an asset of a business needs to fulfill?
Darina [25.2K]

Answer:

<h2>✒️Answer:</h2>

<u>Two conditions must be satisfied. First, the revenue must be earned, which typically means that the customer has received the good or service. Second, the revenue must have been realized or realizable, implying that the customer has paid or is expected to pay for the merchandise.</u>

Step-by-step explanation:

<h2>#CarryOnLearning</h2>

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