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3 years ago

13

Determine the equations of the asymptotes: g(x)=

rmula1" title="\frac{2x^2+1}{x+3}" alt="\frac{2x^2+1}{x+3}" align="absmiddle" class="latex-formula">

1 answer:

Likurg_2 [28]3 years ago

8 0

Answer:

x = -3
y = 2x -6

Step-by-step explanation:

The vertical asymptote is found where the denominator is zero, at x = -3.

The slant asymptote is the quotient of the division: 2x -6.

g(x) = (2x^2+1)/(x +3)

g(x) = 2x -6 +19/(x+3)

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