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3 years ago

13

Determine the equations of the asymptotes: g(x)=

rmula1" title="\frac{2x^2+1}{x+3}" alt="\frac{2x^2+1}{x+3}" align="absmiddle" class="latex-formula">

1 answer:

Likurg_2 [28]3 years ago

8 0

Answer:

x = -3
y = 2x -6

Step-by-step explanation:

The vertical asymptote is found where the denominator is zero, at x = -3.

The slant asymptote is the quotient of the division: 2x -6.

g(x) = (2x^2+1)/(x +3)

g(x) = 2x -6 +19/(x+3)

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4 years ago

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For questions 1 - 8, find f-'(x), the inverse of f(x). 1. f(x)= x + 12 2. f(x)= -2 3. f(x)=2x +12 4. f(x)= 3x -4 5. f(x)= 2x + 3

Alexxx [7]

Answer:

1) inverse: x - 12

2) inverse: 3x + 6

3) inverse: x/2 - 6

4) inverse: x/3 + 4/3

5) inverse: 3x - 3/2

6) inverse: -3x/2 + 15/2

7) inverse: x/5 - 3

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3 years ago

enyata [817]

Answer:

There are 24 ways to select one book of each type.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

It is provided that there are 6 different biographies and 4 different mystery novels on a bookshelf.

Compute the number of ways to select a biography as follows:

Number of ways to select a biography =

$={6\choose 1}\\\\=\frac{6!}{1!(6-1)!}\\\\=\frac{6\times 5!}{1\times 5!}\\\\=6$

There are 6 ways to select a biography.

Compute the number of ways to select a mystery novel as follows:

Number of ways to select a mystery novel =

$={4\choose 1}\\\\=\frac{4!}{1!(4-1)!}\\\\=\frac{4\times 3!}{1\times 3!}\\\\=4$

There are 4 ways to select a mystery novel.

Then the total number of way to select one book of each type is:

${6\choose 1}\times {4\choose 1}=6\times 4=24$

Thus, there are 24 ways to select one book of each type.

6 0

3 years ago