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andreev551 [17]
3 years ago
6

In 1980, James planted a tree that was 1 foot tall. In 1996, that same tree was 51 feet tall. James finds that the height of the

tree can be modeled by the
radical function H (t) = v kt + 1 where H (t) is the height of the tree in feet, t, is the number of years since 1980, and k is a specific constant. What
is the value of k?
Mathematics
1 answer:
Rashid [163]3 years ago
7 0
Divide and see what you get = 51
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Which number sequence follows the rule multiply by 3, starting from 4?
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Answer

12, 36, 108, 324
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8 0
3 years ago
M is the midpoint of segment CS. C is at (-8, 2) M is at the origin. What are the coordinates of S?
ahrayia [7]
C(-8,2) and M(0,0) , since M is at the origin. Let x₁ and y₁ be the
coordinates of S →s(x₁ , y₁)

C(-8,2) and S(x₁ , y₁)
The coordinates of M, the midpoint of CS are M(x₂ , y₂)

a) x₂ = (-8 + x₁)/2 , but x₂ = 0, then :
0 = -4+x₁/2 and x₁ = 8

b) y₂ = (2+y₁)/2 , but y₂ = o, then:
0 = 2+ y₁/2  and y₂ = -2

Then the coordinates of  S are S(8 , -2)
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
4. Solve the system using substitution.
Yuri [45]

Answer:

A

Step-by-step explanation:

-3+2=-1 and (9)- 8=1

3 0
3 years ago
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