Answer:
x=151/64 y=9/8 z=-51/32
Step-by-step explanation:
2x+2y+5z- (2x-y+z)=-1-2
3y+4z=-3
2x+2y+5z- (2x+4y-3z)=-1-14
-2y+8z=-15
We have two equations 3y+4z=-3 and -2y+8z=-15 (We get it due to elimination method)
3y+4z=-3 (2)
-2y+8z=-15 (-3)
6y+8z=-6
6y-24z=45
(6y+8z)- (6y-24z)= -6-45
32z=-51
z=-51/32
3y-204/32=-3
3y= -96/32+204/32
3y=108/32
y=36/32=9/8
2x+2*9/8+5*(-51/32)=-1
2x+9/4-255/32=-1
2x+72/32-255/32=-1
2x-183/32=-32/32
2x=151/32
x=151/64
Answer:
The least score the student can get is 71 to get an overall B average at the end of the year.
Step-by-step explanation:
Let the score she needs to get be = x
We now have to take the mean of all the five subjects <em>(including x)</em> and equate it to the least score she can have to get a B grade.
Let us take the least score the student needs to get a B grade to be 85
Mean of all 5 scores =




The least score the student can get is 71 to get an overall B average at the end of the year.
Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.
Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by

But, we assume that the train accelerates from rest, thus

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).
Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.
Answer:
on the x-axis
Step-by-step explanation:
it is located on the x axis because it is not technically in any quandrant. it is however, on an axis.
i don't know sorry this is hard to do