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love history [14]
3 years ago
10

The price of a new apple ipod has increased by 1/4. if the original price of the apple was $200, what is the price today? $150 $

250 $200 $175 none of these
Mathematics
2 answers:
marusya05 [52]3 years ago
8 0
The price today is 250.

You first multiply 200 by .25 (which is the decimal form of 1/4). This will give you 50. After that, you add the 50 to the 200 to show the increase of 1/4.
vlada-n [284]3 years ago
6 0

Answer: The price today = $250

Step-by-step explanation:

Given : The original price of apple was  $200.

The price of a new apple ipod has increased by 1/4.

Then , the new price =(Original price)  +(\dfrac{1}{4}) x (Original price)

= (Original price) ( 1+\dfrac{1}{4} )

(\$200)(\dfrac{5}{4})=\$250

Hence, the price of ipod today = $250

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Read 2 more answers
50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

P(t)=6.10t^2-9.28t+16.43

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

Differentiate. Use the power rule:

P'(t)=6.10(2t)-9.28(1)

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P'(t)=12.20t-9.28

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P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

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