To start this problem, we know that one of the three pieces that the string is cut into is 15 meters longer than the others. Subtract 15 from 42 to get 27.
Then, from there, you can cut that number (<em>divide</em>) by three to get the length of the two shorter strings. Simply add the 15 meters you didn't use yet to one of the pieces to find the longer string, and you have your lengths.
Hope this helps!
-refrac532
Answer:
No they don't.
LINK TO PICTURE OF WORK - My uploads aren't working my apologies.
https://tex.z-dn.net/?f=A%3A%5C%5C(2*2*2)%2B(3*2*2)%2B(3*2*2)%3D%5C%5C(4*2)%2B(6*2)%2B(6*2)%3D%5C%5C8%2B12%2B12%3D%5C%5C20%2B12%3D%5C%5C32%20cm%5E2%5C%5C%5C%5CB%3A%5C%5C(1*3*2)%2B(1*4*2)%2B(3*4*2)%3D%5C%5C(3*2)%2B(4*2)%2B(12*2)%3D%5C%5C6%2B8%2B24%3D%5C%5C14%2B24%3D%5C%5C38%20cm%5E2
Answer: Hello your question is incomplete attached below is the missing
n ( 1 + n )
Step-by-step explanation:
P( Bob hits target ) = 1/3
P( Eve hits target ) = 2/3
P( Carol hits target ) = 1
<u>Compute the P that Bob wins in a duel against Eve alone</u>
P(Bob hits the target in first shot ) = n = 1/3
P(Bob hits the target in second shot ) = n^2 = ( 1/3 * 1/3 ) = 1/9
hence the probability of Bob winning( i.e. P( Bob wins Event E1 ) = n + n^2 = n ( 1 + n )
Answer:
The markup percentage is 61.2
Step-by-step explanation:
Given as :
The cost price of each ornaments = $23
The sell price of each ornament = $37.08
Let The markup percentage = x
<u>Now, According to question</u>
Markup percentage =
× 100
Or, x% = 
Or, x% = 
Or, x% = 0.612
∴ x = 0.612 × 100
I.e x = 61.2
So, The The markup percentage = x = 61.2
Hence, The markup percentage is 61.2 Answer
Answer:
x=1y
Step-by-step explanation: