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Answer:
The points of the dilated figure would be at (-2, 10), (2, 6), and (-8, 4); an image of the figure is attached.
Step-by-step explanation:
First we translate the center of dilation and figure so the origin becomes the center of dilation.
Since the point (2, 2) is our center of dilation, we must translate it left 2 and down 2 to make the origin the center; this means we map every point
(x, y)→(x-2, y-2)
The scale factor of 2 means that each point will be multiplied by 2; this gives us the rule
(x, y)→(2x-4, 2y-4)
Lastly we will translate the figure right 2 and up 2 to move it back to its original position; this gives us the rule
(x,y)→(2x-4+2, 2y-4+2) = (2x-2, 2y-2)
The first point in the original figure, at the top, is (0, 6). Applying the transformation gives us
(0, 6)→(2*0-2, 2*6-2) = (0-2, 12-2) = (-2, 10)
The point on the right of the pre-image is (2, 4). Applying the transformation rule gives us
(2, 4)→(2*2-2, 2*4-2) = (4-2, 8-2) = (2, 6)
The point on the left of the pre-image is at (-3, 3). Applying the transformation rule, we have
(-3, 3)→(-3*2-2, 3*2-2) = (-6-2, 6-2) = (-8, 4)
The polynomials are closed under subtraction when polynomial 5x − 6 is subtracted from is
will be a polynomial.
Polynomial is an algebraic expression that can involve variables with nonnegative integer terms and constants.
Given
Polynomial 5x -6 and .
Similar terms are terms having the same variables with the same degree.
- When we subtract polynomials, we combine like terms: 3x² is the only x² term.
- We have -6x and subtract 5x from it; this gives us -11x.
- We have 2 and subtract -6 from it; when we subtract a negative, we add the opposite, which means we have 2--6=2+6=8.
Therefore,
The polynomials are closed under subtraction when polynomial 5x − 6 is subtracted from 3x2 − 6x+ 2 is;
Hence, the polynomials are closed under subtraction when polynomial 5x − 6 is subtracted from is
will be a polynomial.
To know more about Polynomial click the link given below.
Answer: (c)
Step-by-step explanation:
Given
The inequality is
Solving the above inequality
Thus, option (c) is correct.