Question

A transformer consists of 290 primary windings and 816 secondary windings. Part a: If the potential difference across the primary coil is 23.0 V , what is the voltage across the secondary coil?
Part b: If the potential difference across the primary coil is 23.0 V , what is the current in the secondary coil if it is connected across a 100 Ω resistor? Express your answer in amperes to three significant figures.

Answer 1

Answer:

(A) 64.7172 VOLT (B) 6.471 A

Explanation:

We have given number of turns in primary that is $N_1=290$

And number of turns in secondary that is $N_2=816$

Primary voltage $V_1=23 volt$

(a) We have to find the secondary voltage  

For transformer we know that $\frac{V_1}{V_2}=\frac{N_1}{N_2}$

$\frac{23}{V_2}=\frac{290}{816}$

$V_2=64.7172volt$

(b) It is given that a resistance of 100 ohm is connected across secondary so current in secondary $i=\frac{V}{R}=\frac{64.7172}{100}=6.471 A$