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Vika [28.1K]
3 years ago
13

In the expression 3x²y + 4x – 5x’y, are the terms 3x’y

Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

Yes. 3x²y and -5x²y are like terms because the variables x and y have the same exponents.

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How do you do the distributive property for 7*7
Troyanec [42]

The distributive property: a(b + c) = ab + ac

7 × 7 = 7 × (10 - 3) = (7)(10) - (7)(3) = 70 - 21 = 49

7 × 7 = 7 × (5 + 2) = (7)(5) + (7)(2) = 35 + 14 = 49

7 0
3 years ago
An art studio charges a start-up fee to cover art supplies, plus an additional fee per class. The graph shows the total cost for
Studentka2010 [4]

Answer/Step-by-step explanation:

✔️The rate of change can be calculated using the coordinates of any two points on the graph. Let's use (2, 60) and (3, 75):

rate of change = \frac{y_2 - y_1}{x_2 - x_1} = \frac{75 - 60}{1} = \frac{15}{1} = 15

Rate of change (m) = 15

✅In the context of this situation, the rate of change can be interpreted to be the additional fee per class. Thus, an additional fee per class cost $15.

✔️Initial value is the same as the y-intercept.

To find the y-intercept (b), substitute m = 15, x = 2, and y = 60 into y = mx + b.

Thus:

60 = 15(2) + b

60 = 30 + b

60 - 30 = b

30 = b

b = 30

The initial value/y-intercept = $30

✅In this context, $30 is the start-up fee to cover art supplies.

5 0
3 years ago
Please Answer these 3 question
Vadim26 [7]

Answer:

5.

Alvin is a proportion relation with a rise/run of 10/1. Contrary Isabelle pays 3 dollars to rent shoes hence the 1st game cost 13 dollars and then the second game 6.

(2,20) means they are on the second game and the cost is 20 dollars

7.

y= 10x

5 0
3 years ago
Ian multiplied a number by 5 he then multiplied that product by 2 what digit is in the ones place of the final product
Lady_Fox [76]
IF the original number was an integer, then the digit in the ones place of the final product is a zero ( 0 ). If it wasn't an integer, then any digit can be in the ones place.
7 0
3 years ago
Read 2 more answers
If $10,500 is deposited in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 y
algol [13]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10500\\ r=rate\to 2.99\%\to \frac{2.99}{100}\dotfill &0.0299\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=10500\left(1+\frac{0.0299}{1}\right)^{1\cdot 5}\implies A=10500(1.0299)^5\implies A\approx 12166.47

5 0
3 years ago
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