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ASHA 777 [7]
3 years ago
14

Select ALL the correct answers. Let f(t) be the amount of garbage, in tons, produced by a city, and let t be the time in years a

fter 2000. Which statements are true for the given function? The dependent variable is f(t). When f(12) = 2,155, the 12 represents "12 tons of garbage produced," and the 2,155 represents "the year 2155." When f(4) = 1,458.6, the 4 represents "the year 2004," and the 1,458.6 represents "1,458.6 tons of garbage produced." The dependent variable is t. When f(2) = 1,323, the 2 represents "the year 2002," and the 1,323 represents "1,323 tons of garbage produced." The independent variable is t. The independent variable is f(t).
Mathematics
2 answers:
sladkih [1.3K]3 years ago
8 0

we are given

f(t) be the amount of garbage, in tons, produced by a city

t be the time in years after 2000

Since, f(t) is dependent on t

so, t is independent

and f(t) is dependent

f(4)=1458.6 means t=4 or 2004

and amount of garbage is 1458.6 tons

f(2)=1323 means t=2 or 2002

and amount of garbage is 1323 tons ...........Answer


Brilliant_brown [7]3 years ago
4 0

Answer:

Its graph number 2 on ed.

Step-by-step explanation:

Just took the assignment its correct!

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Mr. Cruz fills a 3-gallon water cooler for a family picnic. He brings plastic cups that each hold 12 fluid ounces of water. How
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2 years ago
The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard devia
KengaRu [80]

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-70}{4}

The values of the cumulative distribution function of W, denoted by \phi , can be found in the attached file. Lets call y = \frac{z-70}{4} . We have

0.1 = P(X > z) = P(\frac{X-70}{4} > \frac{z-70}{4}) = P(W > y) = 1-\phi(y)

Thus

\phi(y) = 1-0.1 = 0.9

by looking at the table, we find that y = 1.28, therefore

\frac{z-70}{4} = 1.28\\z = 1.28*4+70 = 75.12

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .

Download pdf
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