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3 years ago

The polyatomic ion with the formula HPO42- is called

Mathematics

2 answers:

Artyom0805 [142]3 years ago

8 0

Answer : The polyatomic ion with the formula $HPO_4^{2-}$ is called hydrogen phsophate ions.

Explanation :

The rules for naming the ionic compounds with polyatomic ion is given as :

The positive ion (cation) is written first.
The negative ion (anion) is written next.
The suffix is added at the end of the negative ion (anion). The suffix used is '-ate'.

In $HPO_4^{2-}$ , hydrogen ion combine with phosphate ion to give hydrogen phosphate ion.

Hence, the polyatomic ion with the formula $HPO_4^{2-}$ is called hydrogen phsophate ions.

schepotkina [342]3 years ago

6 0

Answer:

hydrogen phosphate

Step-by-step explanation:

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Drag and drop the terms that match each expression

IceJOKER [234]

Answer: Where is the question?

Step-by-step explanation:

3 0

2 years ago

Admission to a baseball game is $2.50 for general admission and $5.00 for reserved seats. The receipts were $2882.50 for 876 pai

Nikolay [14]

Answer:

599 general admission tickets were sold while 277 reserved seats admission tickets were sold

Step-by-step explanation:

Here, we want to know the number of each types of tickets sold.

Let the number of general admission ticket be x while the number of reserved seats ticket be y

Mathematically since the total of both tickets is 876;

then;

x + y = 876 ••••••••••••(i)

The total amount of money generated from general admission is cost of general admission ticket * the number of general admission tickets sold = $2.50 * x = $2.50x

The total amount of money generated from reserved seat admission tickets sales is cost of reserved seat admission ticket * the number of reserved seats admission ticket sold = $5 * y = $5y

Adding both gives $2882.50

Thus;

2.5x + 5y = 2882.5 •••••••••(ii)

Now, from i, let’s say x = 876 -y

Let’s insert this into ii

2.5(876-y) + 5y = 2882.5

2190 -2.5y + 5y = 2882.5

2190 + 2.5y = 2882.5

2.5y = 2882.5 - 2190

2.5y = 692.5

y = 692.5/2.5

y = 277

Recall;

x = 876 -y

Thus;

x = 876 - 277 = 599

4 0

3 years ago

Niko works at a fast-food restaurant.

Doss [256]

Answer:

Step-by-step explanation:

so he worked 132 hrs in 4 weeks..he worked 6 days per week....

6 * 4 = 24 days...so he worked 132 hrs in 24 days

132 / 24 = 5.5 (or 5 1/2) hrs per day <===

3 0

3 years ago

Ples help me find slant assemtotes

FrozenT [24]

A polynomial asymptote is a function $p(x)$ such that

$\displaystyle\lim_{x\to\pm\infty}(f(x)-p(x))=0$

$(y+1)^2=4xy\implies y(x)=2x-1\pm2\sqrt{x^2-x}$

Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form $p(x)=ax+b$ .

Ignore the negative root (we don't need it). If $y=2x-1+2\sqrt{x^2-x}$ , then we want to find constants $a,b$ such that

$\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0$

We have

$\sqrt{x^2-x}=\sqrt{x^2}\sqrt{1-\dfrac1x}$
$\sqrt{x^2-x}=|x|\sqrt{1-\dfrac1x}$
$\sqrt{x^2-x}=x\sqrt{1-\dfrac1x}$

since $x\to\infty$ forces us to have $x>0$ . And as $x\to\infty$ , the $\dfrac1x$ term is "negligible", so really $\sqrt{x^2-x}\approx x$ . We can then treat the limand like

$2x-1+2x-ax-b=(4-a)x-(b+1)$

which tells us that we would choose $a=4$ . You might be tempted to think $b=-1$ , but that won't be right, and that has to do with how we wrote off the "negligible" term. To find the actual value of $b$ , we have to solve for it in the following limit.

$\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-4x-b)=0$

$\displaystyle\lim_{x\to\infty}(\sqrt{x^2-x}-x)=\frac{b+1}2$

We write

$(\sqrt{x^2-x}-x)\cdot\dfrac{\sqrt{x^2-x}+x}{\sqrt{x^2-x}+x}=\dfrac{(x^2-x)-x^2}{\sqrt{x^2-x}+x}=-\dfrac x{x\sqrt{1-\frac1x}+x}=-\dfrac1{\sqrt{1-\frac1x}+1}$

Now as $x\to\infty$ , we see this expression approaching $-\dfrac12$ , so that

$-\dfrac12=\dfrac{b+1}2\implies b=-2$

So one asymptote of the hyperbola is the line $y=4x-2$ .

The other asymptote is obtained similarly by examining the limit as $x\to-\infty$ .

$\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0$

$\displaystyle\lim_{x\to-\infty}(2x-2x\sqrt{1-\frac1x}-ax-(b+1))=0$

Reduce the "negligible" term to get

$\displaystyle\lim_{x\to-\infty}(-ax-(b+1))=0$

Now we take $a=0$ , and again we're careful to not pick $b=-1$ .

$\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-b)=0$

$\displaystyle\lim_{x\to-\infty}(x+\sqrt{x^2-x})=\frac{b+1}2$

$(x+\sqrt{x^2-x})\cdot\dfrac{x-\sqrt{x^2-x}}{x-\sqrt{x^2-x}}=\dfrac{x^2-(x^2-x)}{x-\sqrt{x^2-x}}=\dfrac
 x{x-(-x)\sqrt{1-\frac1x}}=\dfrac1{1+\sqrt{1-\frac1x}}$

This time the limit is $\dfrac12$ , so

$\dfrac12=\dfrac{b+1}2\implies b=0$

which means the other asymptote is the line $y=0$ .

4 0

3 years ago

A coin is being flipped 400 times. What is the probability of it landing on heads at most 170 times, rounded to the nearest tent

lisabon 2012 [21]

Hello!

We have two probabilities we can use; we have 170/400, for our experiment, and 1/2, which is our theoretical probability.

To solve, we just multiply the two probabilities.

$\frac{170}{400}(1/2)$ =0.2125≈21.3

Therefore, we have about a 21.3% chance of this event occurring.

I hope this helps!

8 0

3 years ago